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2 years ago

6

4 friends evenly divided up an n-slice pizza. One of the friends, Harris, ate 1 fewer slice than he received. How many slices of

pizza did Harris eat? Write your answer as an expression. Pls answer fast I'm taking a test!!

1 answer:

atroni [7]2 years ago

6 0

Answer:

7

Step-by-step explanation:

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Find an antiderivative F(x) with F′(x) = f(x) = 6 + 24x^3 + 18x^5 and F(1)=0.

7nadin3 [17]

Answer:

The antiderivative is $F(X) = 6x + 6x^4 + 3x^6 - 15$ .

Step-by-step explanation:

Antiderivative F(x)

This is the integral of $F^{\prime}(x)$

So

F′(x) = f(x) = 6 + 24x^3 + 18x^5

Then:

$F(x) = \int (6 + 24x^3 + 18x^5) dx$

$F(x) = 6x + \frac{24x^4}{4} + \frac{18x^6}{6} + K$

$F(x) = 6x + 6x^4 + 3x^6 + K$

F(1)=0

$F(X) = 0$ when $x = 1$ . We use this to find K.

$F(x) = 6x + 6x^4 + 3x^6 + K$

$0 = 6 + 6 + 3 + K$

$K = -15$

Thus

The antiderivative is $F(X) = 6x + 6x^4 + 3x^6 - 15$ .

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3 years ago

Which of the following systems of linear equations has an infinite number of solutions?

arlik [135]

Answer:

{ y = 3x + 3

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2 years ago

Without further study, you forget things as time passes. A model of human memory gives the percentage, p, of acquired knowledge

PIT_PIT [208]

Answer:

42.69% of information is acquired by the student in two weeks.

Step-by-step explanation:

We are given the following in the question:

$p = (100 -a)e^{-bt} + a$

where a and b are constants.

$a = 18\\b = 0.6$

p tells us about the percentage of acquired knowledge that a person retains after t weeks.

We have to find the percentage of knowledge acquired in two week.

We put t = 2

$p = (100 -18)e^{-(0.6)(2)} + 18\\p = 42.69$

Thus, 42.69% of information is acquired by the student in two weeks.

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3 years ago

The plutonium isotope has half life

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Answer:

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The different isotopes have different "half-lives" – the time it takes to lose half of its radioactivity. Pu-239 has a half-life of 24,100 years and Pu-241's half-life is 14.4 years. Substances with shorter half-lives decay more quickly than those with longer half-lives, so they emit more energetic radioactivity.

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