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IgorLugansk [536]
3 years ago
8

Taylor Systems has just issued preferred stock. The stock has a 10​% annual dividend and a $ 110 par value and was sold at ​$119

.90 per share. In​ addition, flotation costs of ​$6.60 per share were paid. Calculate the cost of the preferred stock
Business
1 answer:
shutvik [7]3 years ago
4 0
Cost of preferred stock Taylor Systems has just issued preferred stock. The stock has a 12 % annual dividend and a $100 par value and was sold at $97.50 per shar
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Agent Emily's listing was sold by another agent in her brokerage. Emily is entitled to a:______.a. selling side commission.
GaryK [48]
I think it’s C but not really sure
5 0
3 years ago
Suppose you believe that Florio Company's stock price is going to decline from its current level of $82.50 sometime during the n
Lunna [17]

Answer:

$19.9

Explanation:

According to the given situation the computation of pre-tax net profit is shown below:-

Net pre-tax profit = Option exercised per share  + Actual stock price at the end + Profit - Option premium

= $85 + $60 + $25 - $5.10

= $19.9

Therefore for computing the pre-tax net profit we simply applied the above formulas.

4 0
3 years ago
The budget director for Kanosh Cleaning Services prepared the following list of expected selling and administrative expenses. Al
Harrizon [31]

Answer:

Kanosh Cleaning Services

a. Schedule of Cash Payments for S&A Expenses

                                                                       October November December

Equipment lease expense                                     $7,500  $7,500    $7,500

Prior month’s salary expense, 100%                               0    8,200       8,700  

Cleaning supplies                                                     2,800    2,730      3,066

Insurance premium                                                  7,200            0              0

Depreciation on computer                                              0            0              0

Rent                                                                           1,700      1,700        1,700

Miscellaneous expenses                                           700         700          700

Total disbursements for operating expenses  $19,900  $20,830  $21,666

b. Salaries payable = $9,000

c. Prepaid insurance = $3,600

Explanation:

a) Data and Calculations:

                                                October   November  December

Budgeted S&A Expenses

Equipment lease expense       $7,500        $7,500      $7,500

Salary expense                           8,200          8,700        9,000

Cleaning supplies                      2,800          2,730        3,066

Insurance expense                     1,200          1,200         1,200

Depreciation on computer         1,800          1,800         1,800

Rent                                             1,700          1,700         1,700

Miscellaneous expenses             700             700           700

Total operating expenses    $23,900    $24,330   $24,966

Schedule of Cash Payments for S&A Expenses

                                                                       October November December

Equipment lease expense                                     $7,500  $7,500    $7,500

Prior month’s salary expense, 100%                               0    8,200       8,700  

Cleaning supplies                                                     2,800    2,730      3,066

Insurance premium                                                  7,200            0              0

Depreciation on computer                                              0            0              0

Rent                                                                           1,700      1,700        1,700

Miscellaneous expenses                                           700         700          700

Total disbursements for operating expenses  $19,900  $20,830  $21,666

b. Salaries payable = $9,000

c. Prepaid insurance = $3,600 ($7,200 - $3,600)

6 0
2 years ago
Demand per hour for gasoline at a local station is normally distributed with a mean of 875 gallons and std deviation of 55 gallo
marusya05 [52]

The probability that demand is greater than 1800 gallons over a 2 hour period is : 0.5

<u>Given data :</u>

Mean value of gasoline per hour = 875 gallons

Standard deviation = 55 gallons

<h3>Determine the probability of demand being greater than 1800 gallons over 2 hours </h3>

Demand for gas in 1 hour = X₁

Demand for gas in 2 hours = X₁ + X₂

Therefore ; ( X₁ + X₂) ~ N ( u₁+u₂, sd₁² + sd₂² )

In order to  calculate probabilities for normals apply the equation below

Z = ( X- u ) / sd

where : u = 1800, sd = √ ( 55² + 55² ) = 77.78

using the z-table

P( Y > 1800) = P( Z > ( 1800 - 1800 ) / 77.78)

                    = P( Z>0 ) = 0.5

Hence we can conclude that The probability that demand is greater than 1800 gallons over a 2 hour period is : 0.5.

Learn more about probability : brainly.com/question/24756209

#SPJ1

5 0
2 years ago
Suppose that the market demand curve for bean sprouts is given by P = 1,660 - 4Q, where P is the price and Q is total industry o
a_sh-v [17]

Answer:

In equilibrium, total output by the two firms will be option e= 300.  

Q = q_{1} + q_{2}

Q = 100 + 200

Q = 300

Explanation:

Data Given:

Market Demand Curve = P = 1660-4Q

where, P = price and Q = total industry output

Each firm's marginal cost = $60 per unit of output

So, we know that Q =  q_{1} + q_{2}

where q_{} being the individual firm output.

Solution:

P = 1660-4Q

P = 1660- 4(q_{1} + q_{2})

P = 1660 - 4q_{1} - 4q_{2}

Including the marginal cost of firm 1 and multiplying the whole equation by q_{1}

Let's suppose new equation is X

X =  1660q_{1} - 4q_{1} ^{2} - 4q_{1}q_{2} - 60q_{1}

Taking the derivative w.r.t to q_{1}, we will get:

X^{'} = 1660 - 8q_{1} - 4q_{2} - 60 = 0

Making rearrangements into the equation:

8q_{1} + q_{2} = 1660 - 60

8q_{1} + q_{2} = 1600

Dividing the whole equation by 4

2q_{1} +q_{2} = 400

Solving for q_{1}

2q_{1} = 400 - q_{2}

q_{1} = 200 - 0.5 q_{2}  

Including the marginal cost of firm 1 and multiplying the whole equation by q_{2}

P = 1660 - 4q_{1} - 4q_{2}

Let's suppose new equation is Y

Y =  1660q_{2} - 4q_{1}q_{2} -4q_{2} ^{2} - 60q_{2}

Pugging in the value of q_{1}

Y =  1660q_{2} - 4q_{2}(200 - 0.5 q_{2}) -4q_{2} ^{2} - 60q_{2}

Y =  1660q_{2} - 800q_{2} +2q_{2} ^{2} -4q_{2} ^{2} - 60q_{2}

Y =  1600q_{2} - 800q_{2} -2q_{2} ^{2}

Taking the derivative w.r.t q_{2}

Y^{'} = 1600 - 800 - 4q_{2} = 0

Solving for q_{2}

4q_{2} = 800

q_{2} = 200

q_{1} = 200 - 0.5 q_{2}

Plugging in the value of q_{2} to get the value of q_{1}

q_{1} = 200 - 0.5 (200)

q_{1} = 200 - 100

q_{1} = 100

Q = q_{1} + q_{2}

Q = 100 + 200

Q = 300

Hence, in equilibrium, total output by the two firms will be option

e= 300.

5 0
3 years ago
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