Answer:
12.96
Step-by-step explanation:
54 percent *24
= (54/100)*24
= (54*24)/100
= 1296/100 = 12.96
Now we have: 54 percent of 24 = 12.96
Question: What is 54 percent of 24?
We need to determine 54% of 24 now and the procedure explaining it as such
Step 1: In the given case Output Value is 24.
Step 2: Let us consider the unknown value as x.
Step 3: Consider the output value of 24 = 100%.
Step 4: In the Same way, x = 54%.
Step 5: On dividing the pair of simple equations we got the equation as under
24 = 100% (1).
x = 54% (2).
(24%)/(x%) = 100/54
Step 6: Reciprocal of both the sides results in the following equation
x%/24% = 54/100
Step 7: Simplifying the above obtained equation further will tell what is 54% of 24
x = 12.96%
Therefore, 54% of 24 is 12.96
It affects the answer because parentheses signifies or implies that yoy are doing the operation inside of their that step comes first because if you forget about that step and move on it will affect your answer and you will get it wrong write this down
Answer:
0.9 for the top box and 1.68 for the bottom box
Step-by-step explanation:
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A regular trapezoid is shown in the picture attached.
We know that:
DC = minor base = 4
AB = major base = 7
AD = BC = lateral sides or legs = 5
Since the two legs have the same length, the trapezoid is isosceles and we can calculate AH by the formula:
AH = (AB - DC) ÷ 2
= (7 - 5) ÷ 2
= 2 ÷ 2
= 1
Now, we can apply the Pythagorean theorem in order to calculate DH:
DH = √(AD² - AH²)
= √(5² - 1²)
= √(25 - 1)
= √24
= 2√6
Last, we have all the information needed in order to calculate the area by the formula:

A = (7 + 5) × 2√6 ÷ 2
= 12√6
The area of the regular trapezoid is
12√6 square units.
Answer:
(A)398 cubic inches
Step-by-step explanation:
Given a cylindrical piece of iron pipe with the following dimensions:
- Height = 12 inches
- Diameter = 8 inches
Therefore: External radius =4 Inches
Since the wall of the pipe is 0.75 inch thick,
Internal Radius =4-0.75 =3.25 Inches
Volume of a Cylinder = 
Inside Volume of the Pipe

The correct option is A.