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3 years ago

Write an equation for the nth term of the geometric sequences. Then Find a6

Mathematics

1 answer:

love history [14]3 years ago

6 0

Answer: The nth term of a geometric progression is Tn = ar^(n-1)

A. 12

B. 3.6

C. -3/4

D. 0.6

Step-by-step explanation:

The nth term of a geometric progression is Tn = ar^(n-1)

Where Tn= nth term

a = first term

r = common ratio

n = number

A. a6 = (2*6) = 12

B. a6 = (0.6*6) = 3.6

C. a6 = (-1/8*6) = -3/4

D. a6 = (0.1*6) = 0.6

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VikaD [51]

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<h3>How to determine the value of f(3)?</h3>

The table that completes the question is added as an attachment.

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