I’m guessing that this is for systems of equations?
n - nickels
d - dimes
These are the equations you start off with.
n = 5d-2
0.95 = 0.10d+0.05n
Substitute the top equation for n into the variable n in the bottom equation.
0.95 = 0.10d+0.05(5d-2)
Solve for d.
0.95 = 0.10d+0.25d-0.10
1.05 = 0.35d
3 = d
Substitute d into the top equation and solve for n.
n = 5(3)-2
n = 15-3
n = 12
There are 3 dimes and 12 nickels in the coin purse! Hope this helped <3
I believe the answer should be x equals 37
Answer:
y=3
Step-by-step explanation:
m=0
b=3
9514 1404 393
Answer:
1
Step-by-step explanation:
The third term is g. It is equivalent to 1g. (A coefficient of 1 is rarely shown.) The coefficient is the constant multiplier of the variable expression. In the third term, the coefficient is 1.
Step-by-step explanation:
there is no big "trick" involved.
you just need to do the multiplication and then move the terms into the right spot, so that the x-, y- and constant terms are in the same place as the generic Ax + By = C
y + 5 = 4(x + 1)
y + 5 = 4x + 4
-4x + y = -1
or (after multiplying both sides by -1)
4x - y = 1
yes, B = 1 (or -1), so you could write 1y (or -1y) instead of only y (or -y).
but nobody does that.