3 years ago

FORM A CUBIC POLYNOMIAL WHOSE ZEROS ARE -3,-1 AND 2

Mathematics

1 answer:

Firdavs [7]3 years ago

7 0

$(x+3)(x+1)(x-2)=\\(x^2+x+3x+3)(x-2)=\\(x^2+4x+3)(x-2)=\\x^3-2x^2+4x^2-8x+3x-6=\\x^3+2x^2-5x-6$

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Anna11 [10]

ANSWER

See attachment.

EXPLANATION

The given function is

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The parent function is

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The graph of this function is shown in the attachment.

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3 years ago

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bixtya [17]

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Read 2 more answers

Solve 5 tan x = 5√(3) for 0° ≤ x ≤ 180°. a. 60° b. 150° c. 30° d. 120°

ladessa [460]

Answer:

$\boxed{a.\:\:\:60\degree}$

Step-by-step explanation:

The given trigonometric equation is

$5\tan(x)=5\sqrt{3}$ for $0\degree \le x\le 180\degree$ .

We divide through by 5 to get;

$\tan(x)=\sqrt{3}$

We take the inverse tangent of both sides to obtain;

$x=tan^{-1}(\sqrt{3})$

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Since the tangent ratio is positive, it means $x$ could also be in the 3rd quadrant. But this is outside the given range.

Therefore the correct answer is A

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3 years ago