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2 years ago

FORM A CUBIC POLYNOMIAL WHOSE ZEROS ARE -3,-1 AND 2

Mathematics

1 answer:

Firdavs [7]2 years ago

7 0

$(x+3)(x+1)(x-2)=\\(x^2+x+3x+3)(x-2)=\\(x^2+4x+3)(x-2)=\\x^3-2x^2+4x^2-8x+3x-6=\\x^3+2x^2-5x-6$

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If point A, having

Ronch [10]

gradient or slope=y2 -y1

x2 - x1

so for A, p is x1 and 3 is y1..

For B, 6 is x2 and p is y2

2= p - 3

6 - p

2 ( 6 - p) = p - 3

12 - 2p = p - 3

-2p + p = -3 - 12

-p = - 15

p = 15

4 0

2 years ago

The distribution of the number of viewers for the American Idol television show follows a normal distribution with a mean of 26

hjlf

Answer:

Probability that next week's show will have between 30 and 37 million viewers is 0.2248.

Step-by-step explanation:

We are given that the distribution of the number of viewers for the American Idol television show follows a normal distribution with a mean of 26 million with a standard deviation of 8 million.

Let X = number of viewers for the American Idol television show

So, X ~ N( $\mu=26,\sigma^{2}=8^{2}$ )

Now, the z score probability distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = population mean = 26 million

$\sigma$ = standard deviation = 8 million

So, probability that next week's show will have between 30 and 37 million viewers is given by = P(30 < X < 37) = P(X < 37) - P(X $\leq$ 30)

P(X < 37) = P( $\frac{X-\mu}{\sigma}$ < $\frac{37-26}{8}$ ) = P(Z < 1.38) = 0.91621

P(X $\leq$ 30) = P( $\frac{X-\mu}{\sigma}$ $\leq$ $\frac{30-26}{8}$ ) = P(Z $\leq$ 0.50) = 0.69146

Therefore, P(30 < X < 37) = 0.91621 - 0.69146 = 0.2248

Hence, probability that next week's show will have between 30 and 37 million viewers is 0.2248.

4 0

2 years ago

Evaluate the expression. 42+5⋅32−42÷23 CLEAR CHECK 12.625 222 45 59

lidiya [134]

Answer:

$\frac{4604}{23}$ or 200.173913

Step-by-step explanation:

$42+(5)(32)-\frac{42}{23} \\\\=42+160-\\\frac{42}{23}\\\=202-\frac{42}{23} =\frac{4604}{23}$

5 0

3 years ago

The area of a field shaped like a right triangle is 750yd^2.One leg of the field is fenced with wood costing $5/yd. the remainde

Elenna [48]

Assume that
a and b = the two legs of the right triangle.
c = the hypotenuse.

The area of the right triangle is 750 yd², therefore
(1/2)*a*b = 750
ab = 1500 (1)

The perimeter is 150yd, therefore
a + b + c = 150 (2)

Let the side fenced with wood be a, at $5/yd. Sides b and c are fenced with steel at $10/y. The total cost is $1200, therefore
5a + 10b + 10c = 1200
or
a + 2b + 2c = 240 (3)

From (2), obtain
c = 150 - a - b (4)

Substitute (4) into (3)
a + 2b + 2(150 - a - b) = 240
-a + 300 = 240
a = 60

From (1), obtain
60b = 1500
b = 25

From (4), obtain
c = 150 - 60 - 25 = 65

Answer:
A. The length of the leg fenced with wood is 60 yd.
B. The length of the leg fenced with steel is 25 yd.

5 0

3 years ago

A student has gotten the following grades on his tests. What is the minimum grade he must get on the last test in order to have

arsen [322]

The lowest grade that student could get is a 91 or higher

7 0

2 years ago