It is a combination, becasue the order does not matter
C (4,3) = 4! / [3! (4-3)!] = 4
Answer: A and C.
Answer:
1/2.(x+12)=4x-1
x+12=2(4x-1)
x+12=8x-2
Group like terms
12+2=8x-x
14=7x
Divide both sides by 7
x=2
Step-by-step explanation:
G (x) = x + 1 (fog) (x) = x 2 + 3x + 1 ⇒ (fog) (x) = x 2 + 3x + 1 ⇒ f (g (x)) = x 2 + 3x + 1 ⇒ f (x + 1) = x 2 + 3x + 1 Eg x + 1 = p, then x = p - 1. ⇒ f (p) = (p - 1) 2 + 3 ( p - 1) + 1 ⇒ f (p) = p 2 - 2p + 1 + 3p - 3 + 1 ⇒ f (p) = p 2 + p - 1 So f (x) = x 2 + x - 1 - ->
ANSWER IS : x 2 + x - 1
X+3≤ -5+2x
Add 5 to the other side. (the inverse of subtraction, since 5 is negative)
x+8≤2x
Subtract x on both sides.
8≤x <- the answer
I hope this helps!
~kaikers
<u>We are given the equation:</u>
(a + b)! = a! + b!
<u>Testing the given equation</u>
In order to test it, we will let: a = 2 and b = 3
So, we can rewrite the equation as:
(2+3)! = 2! + 3!
5! = 2! + 3!
<em>We know that (5! = 120) , (2! = 2) and (3! = 6):</em>
120 = 2 + 6
We can see that LHS ≠ RHS,
So, we can say that the given equation is incorrect