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stellarik [79]
3 years ago
10

Cindy takes a sheet of paper and cuts from one corner to the opposite corner, making two triangles. If the piece of paper is 5 i

nches long and 5 inches wide, what is the perimeter of one of the triangles(nearest tenth)?
Mathematics
1 answer:
Westkost [7]3 years ago
6 0

Answer:

Perimeter of one of the triangle= 17.071 inch

Step-by-step explanation:

The triangle has:

Perpendicular= 5 inch\\Base = 5 inch \\Diagonal(Hypotenuse)=?

Using the Pythagorean Theorem;

          ( Hypotenuse)^2=(Perpendicular)^2+(Base)^2\\H^2= 5^2+5^2\\H^2=25+25\\H^2=50\\

        H=\sqrt{50}\\or\\H=7.071 inches

The Perimeter of one of the triangle is =

                           Perpendicular+Base+Hypotenuse\\5+5+7.071\\17.071inch

This is equal for the other triangle.

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y''-y'=0\implies z'-z=0\implies z=C_1e^x\implies y=C_1e^x+C_2

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y=\displaystyle\sum_{n\ge0}a_nx^n
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\displaystyle\sum_{n\ge2}n(n-1)a_nx^{n-2}-\sum_{n\ge1}na_nx^{n-1}=0

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\begin{cases}a_0=a_0\\\\a_1=a_1\\\\a_n=\dfrac{a_{n-1}}n&\text{for }n\ge2\end{cases}

We can solve explicitly for a_n quite easily:

a_n=\dfrac{a_{n-1}}n\implies a_{n-1}=\dfrac{a_{n-2}}{n-1}\implies a_n=\dfrac{a_{n-2}}{n(n-1)}

and so on. Continuing in this way we end up with

a_n=\dfrac{a_1}{n!}

so that the solution to the ODE is

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We also require the solution to satisfy y(0)=a_0, which we can do easily by adding and subtracting a constant as needed:

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