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IceJOKER [234]
3 years ago
11

Use a ratio to compare this quantity 3 kg ; 200g

Mathematics
2 answers:
pickupchik [31]3 years ago
8 0

Answer:

the answer is 15:1

Step-by-step explanation:

:))))

Nana76 [90]3 years ago
6 0

9514 1404 393

Answer:

  15 : 1

Step-by-step explanation:

Each kg is 1000 g, so the ratio is ...

  3000 g : 200 g = 30 : 2 = 15 : 1

3 kg is 15 times 200 g.

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Simplify the expression<br> -9(-6+2n)
Wittaler [7]
54 - 18n

Multiply -9 by -6 to get 54.
Multiply -9 by 2n to get 18n.
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The diagonals of rhombus abcd intersect at point
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C 24 inches im possitive
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3 years ago
Sample annual salaries (in thousands of dollars) for employees at a company are listed. 42 36 48 51 39 39 42 36 48 33 39 42 45 (
Sonja [21]

Answer:

a) Data given: 42 36 48 51 39 39 42 36 48 33 39 42 45

\bar X = 41.538

s = 5.317

b) 44.1, 37.8, 50.4, 53.55, 40.95, 44.1, 37.8, 50.4 ,34.65, 40.95, 44.1, 47.25

\bar X = 43.615

s= 5.583

c) 3.5, 3, 4, 4.25, 3.25, 3.25, 3.5, 3, 4, 2.75, 3.25, 3.5, 3.75

\bar X= 3.462

s = 0.443

d) As we can see, the average of part b is 1.05 times the average of part a (1.05 * 41.538 = 43.615) and the average of part c is equal to the average obtained in part a divided by 12 (41.538 / 12 = 3.462).

And that happens because we create linear transformations for the parts b and c and the linear transformation affects the mean.

And you have the same interpretation for the deviation, it is affected by the linear transformation as the mean.

Step-by-step explanation:

For this case we can use the following formulas for the mean and standard deviation:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

Part a

Data given: 42 36 48 51 39 39 42 36 48 33 39 42 45

And if we calculate the mean we got:

\bar X = 41.538

s = 5.317

Part b

For this case we know that each value present a 5% of rise so we just need to multiply each value bu 1.05 and we have this new dataset:

44.1, 37.8, 50.4, 53.55, 40.95, 44.1, 37.8, 50.4 ,34.65, 40.95, 44.1, 47.25

And if we calculate the new mean and deviation we got:

\bar X = 43.615

s= 5.583

Part c

The new dataset would be each value divided by 12 so we have:

3.5, 3, 4, 4.25, 3.25, 3.25, 3.5, 3, 4, 2.75, 3.25, 3.5, 3.75

And the new mean and deviation would be:

\bar X= 3.462

s = 0.443

Part d

As we can see, the average of part b is 1.05 times the average of part a (1.05 * 41.538 = 43.615) and the average of part c is equal to the average obtained in part a divided by 12 (41.538 / 12 = 3,462).

And that happens because we create linear transformations for the parts b and c and the linear transformation affects the mean.

And you have the same interpretation for the deviation, it is affected by the linear transformation as the mean.

5 0
4 years ago
Solve for x<br><br> 15x^2+16x= -4
Klio2033 [76]
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Δ = b²-4ac =256 - 4×15×4 =16

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4 0
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doing all 4 would help but you don't have to do all of them 2 or one is fine with me. but no fake answers
Oduvanchick [21]

Answer:

the picture is kinda blur but nvm

Step-by-step explanation:

3:b

4:b

5:a

6:b

4 0
3 years ago
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