Answer:
- 6 2/3 qt 80%
- 13 1/3 qt 20%
Step-by-step explanation:
It is often convenient to solve a mixture problem by letting a variable represent the quantity of the higher-concentration contributor to the mix.
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We can let x represent the number of quarts of 80% solution needed. Then (20-x) is the number of quarts of 20% solution needed. The amount of salt in the final mix is ...
0.80x +0.20(20-x) = 0.40(20)
0.60x = 0.20(20) . . . . . . . . subtract 0.20(20) and simplify
x = 20/3 = 6 2/3 . . . . . . . . . divide by 0.60; quarts of 80% solution
(20 -x) = 13 1/3 . . . . . . . . . . amount of 20% solution needed
The teacher should mix 6 2/3 quarts of 80% solution with 13 1/3 quarts of 20% solution.
Answer:
m = j + 10
m + 3 = 3x
Step-by-step explanation:
Answer:
1
Explanation:
Radius = C/2π
C is 6.28 and 2*pi is also 6.28
So 6.28/6.28 = 1.
Step-by-step explanation:
3n-5=(-8*6)+(-8*5n) distributive property
3n-5=-48-40n
3n+40n=-48+5 add property
43n=-43 add property
43n/43=-43/43 division property
n=-1
: