Answer:
24s^2, 54s^2, 96s^2
Step-by-step explanation:
Let s represent the initial side length of the cube. Then the area of each face of the cube is A = 6s^2 (recalling that the area of a square of side length s is s^2).
a) Now suppose we double the side length. The total area of the 6 faces of the cube will now be A = 6(2s)^2, or 24s^2 (a 24 times larger surface area),
b) tripled: A = 6(3s)^2 = 54x^2
c) quadrupled? A = 6(4s)^2 = 96s^2
It would be 5*5*5 which is 125 :D
Let's solve your system by substitution.
y=2x+1;y=4x−1
Step: Solve y=2x+1for y:
y=2x+1
Step: Substitute2x+1foryiny=4x−1:
y=4x−1
2x+1=4x−1
2x+1+−4x=4x−1+−4x(Add -4x to both sides)
−2x+1=−1
−2x+1+−1=−1+−1(Add -1 to both sides)
−2x=−2
−2x
−2
=
−2
−2
(Divide both sides by -2)
x=1
Step: Substitute1forxiny=2x+1:
y=2x+1
y=(2)(1)+1
y=3(Simplify both sides of the equation)
Answer:
x=1 and y=3
You put the values of x into the equation to work out y, so the y column would be -5, -1, 3, 7 (for question 6)
For question 7, the y column would be 2,2,0,-2
Use these values to draw the graphs :)
