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Norma-Jean [14]
3 years ago
13

The sides of a hexagon are 2, 3, 2, 4, 7, and 6. Find the perimeter of a similar hexagon with two sides of length 3.

Mathematics
1 answer:
nasty-shy [4]3 years ago
8 0

The first hexagon: 2, 2, 3, 4, 6, 7

The second hexagon: 3, 3, a, b, c, d

The hexagons are similar. Therefore the sides are in proportion.

\dfrac{a}{3}=\dfrac{3}{2}     multiply both sides by 3

a=\dfrac{3}{2}=4.5

\dfrac{b}{4}=\dfrac{3}{2}   multiply both sides by 4

b=\dfrac{3}{2}\cdot4=6

\dfrac{c}{6}=\dfrac{3}{2}     multiply both sides by 6

c=\dfrac{3}{2}\cdot6=9

\dfrac{d}{7}=\dfrac{3}{2}    multiply both sides by 7

d=\dfrac{21}{2}=10.5

The perimeter:

P=4.5+6+9+10.5=30

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\text{d.}\quad a_n=-2.25(2)^{n-1}

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The common ratio is given as 2, so the base of any exponential must be 2 (not -2 or 2.25). The 4th term is negative, so the initial value must be negative (since the multiplying factor is positive). The only selection matching these requirements is d.

You know the general term is ...

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Step-by-step explanation:

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Answer:

No

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with (x₁, y₁ ) = P(- 8, - 10) and (x₂, y₂ ) = Q(- 5, - 12)

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