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lbvjy [14]
3 years ago
5

A limited-edition poster increases in value each year with an initial value of $18. After 1 year and an increase of 15% per year

, the poster is worth $20.70. Which equation can be used to find the value, y, after x years? (Round money values to the nearest penny.)
Mathematics
2 answers:
Roman55 [17]3 years ago
7 0

Answer:

The required equation is y = 18(1.15)^x.

Step-by-step explanation:

Consider the provided information.

The Initial value of poster = $ 18

After 1 year amount of increase = $ 20.70

With the rate of 15% = 0.15

Let future value is y and the number of years be x.

y = 18(1.15)^x

Now verify this by substituting x=1 in above equation.

y = 18(1.15)^1=20.7

Which is true.

Hence, the required equation is y = 18(1.15)^x.

saveliy_v [14]3 years ago
6 0

Answer:y = 18(1.15)^x

Step-by-step explanation:

g o o g ; e

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Which ordered pair is a solution to the inequality -2/3x-4y > 0
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Answer:

The answer would be (-3,-1/2)

Step-by-step explanation:

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3 years ago
A dairy company gets milk from two dairies and then blends the milk to get the desired amount of butterfat. Milk from dairy I co
lisov135 [29]

Answer:

The complete solution and step by step explanation is written below.

<em>Note:</em>

Here is the complete question you were probability asking as you may have unintentionally missed to mention the parts (a) and (b). So, after a little research, I figured out that this was probably the complete question you had meant to ask. So, I am answering based on the reference of this complete question that may indeed clear your concepts.

Complete Question:

<em>A dairy company gets milk from two dairies and then blends the milk to get the desired amount of butterfat. Milk from dairy I costs ​$2.40 per​ gallon, and milk from dairy II costs ​$0.80 per gallon. At most ​$144 is available for purchasing milk. Dairy I can supply at most 50 gallons averaging 3.9​% ​butterfat, and dairy II can supply at most 80 gallons averaging 2.9​% butterfat. Answer parts a and b</em>.

<em>A. How much milk from each supplier should the company buy to get at most 100 gallons of milk with the maximum amount of butterfat? (Also, what IS the maximum amount of butterfat?)</em>

<em>B. The solution from part A leaves both dairy 1 and dairy 2 with excess capacity. Calculate the amount of additional milk each dairy could produce.</em>

Step-by-step explanation:

Let A be number of gallons of the amount of milk the company bought from Dairy 1.

(100 - X) be the number of gallons of the amount of milk the company bought from Dairy 2.

Milk from dairy I costs ​$2.40 per​ gallon and milk from dairy II costs ​$0.80 per gallon.

So, the equation of total cost available for purchasing the milk be:

                            Cost =  2.40A + ( 100 - A)0.80

As $144 is the total cost available for purchasing the milk.

Hence, Cost equation would be as follows:

                             Cost =  2.40A + ( 100 - A)0.80

                               144 =  2.40A + ( 100 - A)0.80

                               144 = 2.40A + 80 - 0.80A

                              1.6A = 64

                            So, A = 64 ÷ 1.6

                                      = 40 gallons

<em>Calculation of gallons of Dairy 1 and Dairy 2:</em>

gallons of Dairy 1 ⇒ A = 40 gallons

gallons of Dairy 1 ⇒ 100 - A = 100 - 40 = 60 gallons

<em>The equation for Fat will be:</em>

Fat for dairy 1 = 40 × 3.9​% = 1.56

Fat for dairy 2 = 60 × 2.9​% = 1.74

ADD = 1.56 + 1.74 = 3.3 %

<em>Calculation Part B:</em>

Dairy 1 will have = 50 - 40 = 10 gallons ( excess)

Dairy 2 will have = 80 - 60 = 20 gallons (excess)

   

Keywords: word problem, equation solving

Learn more about word problems and equation solving from brainly.com/question/8917703

#learnwithBrainly

5 0
3 years ago
I will mark you brainliest and give 50 points if u help and pls I want the answer to both a and b if u give random answers witho
shusha [124]

Answer:

5a. 4w+24≤100

5b. Dimensions=31ft x 19 ft

      Area = 589ft²

Step-by-step explanation:

l=w+12

p=2l+2w

p=2(w+12)+2w

p=2w+24+2w

p=4w+24

The farmer has 100ft of fencing, so maximum that the perimeter (p) can be is 100, meaning (4w+24) has to be less than or equal to 100:

4w+24≤100

For the largest possible perimeter, all 100 of fencing will be used, so allow 100 to be equal to 4w+24)

100=4w+24

4w=76

w=19ft

l=w+12

l=19+12

l=31ft

The dimensions are 31ft x 19ft.

Area=lw

=31*19

=589ft²

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