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Olin [163]
3 years ago
15

Why cannot squares be placed in the hierarchy under trapezoids.

Mathematics
2 answers:
Sveta_85 [38]3 years ago
4 0
They have four equal/90 degree angles (which trapezoids don’t) they have four equal lines as well (trapezoids don’t have equal length lines)
solong [7]3 years ago
3 0
Because the are not the same size
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Solve for the value of R. <br> SOMEONE PLEASE HELP ILL GIVE YOU POINTS AND BRAINLIST ANSWER !!!
lord [1]

Step-by-step explanation:

(3r + 4)  + (8r - 2) = 90

3r + 4 + 8r - 2= 90

11r = 88

r =  \frac{88}{11} \\

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It rained 12 days out of 30 days. Which
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The answer to your question is 4:10
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3 years ago
I will award you brainlist
ExtremeBDS [4]

Answer:

TRUE

Step-by-step explanation:

We are given 2 triangles, ∆ABC and ∆DEF.

For the two trinagles to be considered similar, both must have their set of corresponding angles congruent to each other. That is, their corresponding angles are equal.

From the information given, the following are the set of corresponding angles:

<B = <E = 31°

<B = <D = 90°

<C = <F = 59° [180 - (90+31)]

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3 0
3 years ago
I don’t under stand how to find the area of a region!
rodikova [14]

Answer:

Step-by-step explanation:

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7 0
3 years ago
Use a Venn diagram to answer the question. A survey of 180 families showed that 67 had a​ dog; 52 had a​ cat; 22 had a dog and a
Mice21 [21]

Answer:

There are 13 families had a parakeet only

Step-by-step explanation:

* Lets explain the problem

- There are 180 families

- 67 families had a dog

- 52 families had a cat

- 22 families had a dog and a cat

- 70 had neither a cat nor a​ dog, and in addition did not have a​

 parakeet

- 4 had a​ cat, a​ dog, and a parakeet (4 is a part of 22 and 22 is a part

 of 67 and 520

* We will explain the Venn-diagram

- A rectangle represent the total of the families

- Three intersected circles:

 C represented the cat

 D represented the dog

 P represented the parakeet

- The common part of the three circle had 4 families

- The common part between the circle of the cat and the circle of the

 dog only had 22 - 4 = 18 families

- The common part between the circle of the dog and the circle of the

 parakeet only had a families

- The common part between the circle of the cat and the circle of the

 parakeet only had b families

- The non-intersected part of the circle of the dog had 67 - 22 - a =

  45 - a families

  had dogs only

- The non-intersected part of the circle of the cat had 52 - 22 - b =  

  30 - b families

  had cats only

- The non-intersected part of the circle of the parakeet had c families

  had parakeets only

- The part out side the circles and inside the triangle has 70 families

- Look to the attached graph for more under stand

∵ The total of the families is 180

∴ The sum of all steps above is 180

∴ 45 - a + 18 + 4 + 30 - b + b + c + a + 70 = 180 ⇒ simplify

- (-a) will cancel (a) and (-b) will cancel (b)

∴ (45 + 18 + 4 + 30 + 70) + (-a + a) + (-b + b) + c = 180

∴ 167 + c = 180 ⇒ subtract 167 from both sides

∴ c = 180 - 167 = 13 families

* There are 13 families had a parakeet only

5 0
3 years ago
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