3 years ago

PLEASE HELP WITH THIS PLEASE!!

Mathematics

2 answers:

Nonamiya [84]3 years ago

7 0

Answer:

Step-by-step explanation:

this is the answer I think

Firdavs [7]3 years ago

4 0

Answer is 96

I hope it helped

You might be interested in

What number is equivalent to the following expression 362,880,20!,5•4•3•2•1•4•3•2•1,2880

Y_Kistochka [10]

5!3! means 5(factorial)3(factorial) factorial means to mutiply by everything down to 1...so for example 6! = 6x5x4x3x2x1 So 5!3! means 3) 5x4x3x2x1x3x2x1 ??

i dont know..

5 0

3 years ago

Solve the system of linear equations by graphing 4x + 2y = 8<br> -x + y =- 5

Gnoma [55]

It’s seven my guy ahhhhhhhhhhhhh

4 0

3 years ago

<img src="https://tex.z-dn.net/?f=%28x%5E%7B2%7D%20y%5E4%29%20%5E%7B-3%7D" id="TexFormula1" title="(x^{2} y^4) ^{-3}" alt="(x^{2

Ymorist [56]

Answer:

Step-by-step explanation:

6 0

3 years ago

Please u need to help please

MA_775_DIABLO [31]

Based on the picture she could use wood screen screws to make something similar

8 0

3 years ago

Read 2 more answers

To the nearest tenth, find the perimeter of ABC with vertices A (-2,-2) B (0,5) and C (3,1)

Pavlova-9 [17]

the perimeter will then just be the sum of the distances of A, B and C, namely AB + BC + CA.

$\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\A(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-2})\qquadB(\stackrel{x_2}{0}~,~\stackrel{y_2}{5})\qquad \qquadd = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}\\\\\\AB=\sqrt{[0-(-2)]^2+[5-(-2)]^2}\implies AB=\sqrt{(0+2)^2+(5+2)^2}\\\\\\AB=\sqrt{4+49}\implies \boxed{AB=\sqrt{53}}\\\\[-0.35em]\rule{34em}{0.25pt}\\\\B(\stackrel{x_2}{0}~,~\stackrel{y_2}{5})\qquad C(\stackrel{x_1}{3}~,~\stackrel{y_1}{1})\\\\\\BC=\sqrt{(3-0)^2+(1-5)^2}\implies BC=\sqrt{3^2+(-4)^2}$

$\bf BC=\sqrt{9+16}\implies \boxed{BC=5}\\\\[-0.35em]\rule{34em}{0.25pt}\\\\C(\stackrel{x_2}{3}~,~\stackrel{y_2}{1})\qquad A(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-2})\\\\\\CA=\sqrt{(-2-3)^2+(-2-1)^2}\implies CA=\sqrt{(-5)^2+(-3)^2}\\\\\\CA=\sqrt{25+9}\implies \boxed{CA=\sqrt{34}}\\\\[-0.35em]\rule{34em}{0.25pt}\\\\~\hfill \stackrel{AB+BC+CA}{\approx 18.11}~\hfill$

5 0

3 years ago