Which shows the prime factorization of 36?

Find the value of the power

julsineya [31]

Answer:

Power is the zero at the end of the number like this 56 small 0 at the top right

Step-by-step explanation: Its not just the zero its whatever number is divided by the power it cant go past 50

3 0

2 years ago

Robin, who is self-employed, contributes $4500/year into a Keogh account. How much will he have in the account after 30 years if

pashok25 [27]

Answer:

The amount that would be in the account after 30 years is $368,353

Step-by-step explanation:

Here, we want to calculate the amount that will be present in the account after 30 years if the interest is compounded yearly

We proceed to use the formula below;

A = [P(1 + r)^t-1]/r

From the question;

P is the amount deposited yearly which is $4,500

r is the interest rate = 2.5% = 2.5/100 = 0.025

t is the number of years which is 30

Substituting these values into the equation, we have;

A = [4500(1 + 0.025)^30-1]/0.025

A = [4500(1.025)^29]/0.025

A = 368,353.3309607034

To the nearest whole dollars, this is;

$368,353

4 0

2 years ago

Surface area,<br>pls help

erastovalidia [21]

192
Solution
(2ft)x(12ft)x(8ft)
Answer
192
Sana po makatulong

5 0

2 years ago

Help!! 50 points and brainliest!

Viktor [21]

Answer:

Second choice:

$x=2t$

$y=4t^2+4t-3$

Fifth choice:

$x=t+1$

$y=t^2+4t$

Step-by-step explanation:

Let's look at choice 1.

$x=t+1$

$y=t^2+2t$

I'm going to subtract 1 on both sides for the first equation giving me $x-1=t$ . I will replace the $t$ in the second equation with this substitution from equation 1.

$y=(x-1)^2+2(x-1)$

Expand using the distributive property and the identity $(u+v)^2=u^2+2uv+v^2$ :

$y=(x^2-2x+1)+(2x-2)$

$y=x^2+(-2x+2x)+(1-2)$

$y=x^2+0+-1$

$y=x^2$

So this not the desired result.

Let's look at choice 2.

$x=2t$

$y=4t^2+4t-3$

Solve the first equation for $t$ by dividing both sides by 2:

$t=\frac{x}{2}$ .

Let's plug this into equation 2:

$y=4(\frac{x}{2})^2+4(\frac{x}{2})-3$

$y=4(\frac{x^2}{4})+2x-3$

$y=x^2+2x-3$

This is the desired result.

Choice 3:

$x=t-3$

$y=t^2+2t$

Solve the first equation for $t$ by adding 3 on both sides:

$x+3=t$ .

Plug into second equation:

$y=(x+3)^2+2(x+3)$

Expanding using the distributive property and the earlier identity mentioned to expand the binomial square:

$y=(x^2+6x+9)+(2x+6)$

$y=(x^2)+(6x+2x)+(9+6)$

$y=x^2+8x+15$

Not the desired result.

Choice 4:

$x=t^2$

$y=2t-3$

I'm going to solve the bottom equation for $t$ since I don't want to deal with square roots.

Add 3 on both sides:

$y+3=2t$

Divide both sides by 2:

$\frac{y+3}{2}=t$

Plug into equation 1:

$x=(\frac{y+3}{2})^2$

This is not the desired result because the $y$ variable will be squared now instead of the $x$ variable.

Choice 5:

$x=t+1$

$y=t^2+4t$

Solve the first equation for $t$ by subtracting 1 on both sides:

$x-1=t$ .

Plug into equation 2:

$y=(x-1)^2+4(x-1)$

Distribute and use the binomial square identity used earlier:

$y=(x^2-2x+1)+(4x-4)$

$y=(x^2)+(-2x+4x)+(1-4)$

$y=x^2+2x+-3$

$y=x^2+2x-3$ .

This is the desired result.

3 0

3 years ago

Read 2 more answers

randall borrowed $850 from his parents to make some repairs on his car.He promised to repay the loan by giving his parents at le

sammy [17]

Then, he would take = $850/94 = 9.04

atleast 9.04 weeks for repaying that.......

4 0

3 years ago

Read 2 more answers