Answer:
help me 444
Step-by-step explanation:
<span>Constraints (in slope-intercept form)
x≥0,
y≥0,
y≤1/3x+3,
y</span>≤ 5 - x
The vertices are the points of intersection between the constraints, or the outer bounds of the area that agrees with the constraints.
We know that x≥0 and y≥0, so there is one vertex at (0,0)
We find the other vertex on the y-axis, plug in 0 for x in the function:
y <span>≤ 1/3x+3
y </span><span>≤1/3(0)+3
y = 3.
There is another vertex at (0,3)
Find where the 2 inequalities intersect by setting them equal to each other
(1/3x+3) = 5-x Simplify Simplify Simplify
x = 3/2
Plugging in 3/2 into y = 5-x: 10/2 - 3/2 = 7/2
y=7/2
There is another vertex at (3/2, 7/2)
There is a final vertex where the line y=5-x crosses the x axis:
0 = 5 -x , x = 5
The final vertex is at point (5, 0)
Therefore, the vertices are:
(0,0), (0,3), (3/2, 7/2), (5, 0)
We want to maximize C = 6x - 4y.
Of all the vertices, we want the one with the largest x and smallest y. We might have to plug in a few to see which gives the greatest C value, but in this case, it's not necessary.
The point (5,0) has the largest x value of all vertices and lowest y value.
Maximum of the function:
C = 6(5) - 4(0)
C = 30</span>
Answer:
I cant see, Camera quaily is bad.
Step-by-step explanation:
the difference between a proper fraction and an improper fraction is an improper fraction is a fraction that is bigger then the denominator for example 3/4 is a fraction and 7/4 is an improper fraction
Hey there! :)
Answer:
SA = 144 cm².
Step-by-step explanation:
Find the surface area by calculating the areas of each of the lateral sides and bases:
In this instance, the bases are triangles, so the formula A = 1/2(bh) will be used:
Bases:
A = 1/2(bh)
A = 1/2(4·3)
A = 1/2(12)
A = 6 cm².
There are two bases, so:
6 × 2 = 12 cm²
Find the areas of the lateral sides using A = l × w:
5 × 11 = 55 cm²
4 × 11 = 44 cm²
3 × 11 = 33 cm²
Add up all of the areas:
12 + 55 + 44 + 33 = 144 cm².
