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lesya692 [45]
3 years ago
13

(5,-10) and (15,-20). find the equation of this line.

Mathematics
2 answers:
KATRIN_1 [288]3 years ago
5 0

Answer:

y = -x - 5.

Step-by-step explanation:

The slope of the line is (-20-(-10) /(15-5)

= -10/10 = -1.

Now use the point slope form of a straight line:

y - y1 = m(x - x1)   where m = the slope and (x1, y1) is a point on the line.

So we have:

y - (-10) = -1(x - 5)

y + 10 = -x + 5

y = -x + 5 - 10

y = -x - 5.

Vika [28.1K]3 years ago
3 0

Answer:

y = -x-5

Step-by-step explanation:

slope of the line is =(-20+10) / (15-5) = -10/10 = -1

Now equation of line is y+10=(-1)(x-5)

i.e. y+10= -x +5

i.e y = -x-5

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therefore

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plug x=\sqrt{19}/2 into p( q(x) ) to get answer

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