Answer:
- 892 lb (right)
- 653 lb (left)
Step-by-step explanation:
The weight is in equilibrium, so the net force on it is zero. If R and L represent the tensions in the Right and Left cables, respectively ...
Rcos(45°) +Lcos(75°) = 800
Rsin(45°) -Lsin(75°) = 0
Solving these equations by Cramer's Rule, we get ...
R = 800sin(75°)/(cos(75°)sin(45°) +cos(45°)sin(75°))
= 800sin(75°)/sin(120°) ≈ 892 . . . pounds
L = 800sin(45°)/sin(120°) ≈ 653 . . . pounds
The tension in the right cable is about 892 pounds; about 653 pounds in the left cable.
_____
This suggests a really simple generic solution. For angle α on the right and β on the left and weight w, the tensions (right, left) are ...
(right, left) = w/sin(α+β)×(sin(β), sin(α))
Answer:
19/20
Step-by-step explanation:
A "simplified fraction" in this case is the ratio of two integers.
0.95 = 95/100 (the ratio of two integers), which in turn can be simplified:
95/100 = 19/20
The answer is H= (1/2) b/A
Answer : b
Same distance between consecutive terms.
Answer:
20 ft by 10ft
Step-by-step explanation:
Area of the garden =200 square feet
Let the dimensions of the garden be x and y
Area, xy=200
Since one side is already protected by a barn,
Perimeter of the garden=2x+y
The minimum point of P(y) is the point where its derivative equals zero.
y=20feet
Recall:
xy=200
20x=200
x=10feet
The dimensions of the garden that will require minimum fencing is 20 ft by 10ft
