This question is solved applying the formula of the area of the rectangle, and finding it's width. To do this, we solve a quadratic equation, and we get that the cardboard has a width of 1.5 feet.
Area of a rectangle:
The area of rectangle of length l and width w is given by:

w(2w + 3) = 9
From this, we get that:

Solving a quadratic equation:
Given a second order polynomial expressed by the following equation:
.
This polynomial has roots
such that
, given by the following formulas:
In this question:


Thus a quadratic equation with 
Then


Width is a positive measure, thus, the width of the cardboard is of 1.5 feet.
Another similar problem can be found at brainly.com/question/16995958
Answer:
the closest part the mechanic can chose is 0.5 inch
Step-by-step explanation:
fractional sizes given to the nearest 64th of an inch = 1/64 = 0.0156
the closest size to 0.492in = 0.492 + 0.0156 = 0.5076 inches
approximately, the closest part the mechanic can chose is 0.5 inch
Answer:
Isnt it where you write it in the easiest way to understand it? sorry if its wrong :/
Step-by-step explanation:
What are you solving for? if you are solving for x, then x=(P-12)/(Q-13)