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USPshnik [31]
3 years ago
7

What is the supplement of an angle having a measure of 120 degrees?

Mathematics
1 answer:
kipiarov [429]3 years ago
5 0
The supplementary angle of 120° is 60°.
So your answer is 60 degrees.
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Y - 8 = -10<br> How do I verify the solution ?
prisoha [69]

Answer:

y = -2

Step-by-step explanation:

<u>SOLUTION :-</u>

Solve the equation.

  • Add 8 to both sides in order to isolate the equation.

=> y - 8 + 8 = -10 + 8

=> y = -2

∴ y = -2

<u>VERIFICATION :-</u>

To verify the solution of y , just put the solution (y = -2) in place of y in equation and check whether L.H.S = R.H.S.

L.H.S :-

-2 - 8 = <u>-10</u>

R.H.S. :-

<u>-10</u> (already given)

⇒L.H.S. = R.H.S. (verified)

4 0
2 years ago
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Answer:

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Step-by-step explanation:

7 0
2 years ago
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kondaur [170]

Answer:

\int \dfrac{du}{u}=\log|u|+C

\int u^n du=\dfrac{u^{n+1}}{n+1}+C

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Step-by-step explanation:

a.

\int \dfrac{du}{u}=\log|u|+C    [\because \int \dfrac{dx}{x}=\log |x|+C]

b.

\int u^n du=\dfrac{u^{n+1}}{n+1}+C    [\because \int x^n dx=\dfrac{x^{n+1}}{n+1}+C]

c.

\int \dfrac{du}{u\sqrt{u^2-a^2}}=\dfrac{1}{a}\csc^{-1}(\dfrac{x}{a})+C        [\because \dfrac{adx}{x\sqrt{x^2-a^2}}=\csc^{-1}(\dfrac{x}{a})+C]

3 0
3 years ago
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Answer:

B. Square root

Step-by-step explanation:

using distance formula:

x = √z^2 - y^2

y = √z^2 - x^2

=> z = √x^2 + y^2

5 0
3 years ago
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Is tu parallel to vw? Explain.
Varvara68 [4.7K]

Answer: C

Step-by-step explanation:

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2 years ago
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