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alex41 [277]
3 years ago
14

4(4x-2) + 1 =16x - 7. Solutions

Mathematics
1 answer:
Talja [164]3 years ago
6 0

Answer:

4(4x - 2) + 1 = 16x - 7

16x - 8 + 1 = 16x - 7

16x - 7 = 16x - 7

-7 = -7

0 = 0

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F(\infty)= \int\limits^{\infty}_{-\infty} {f(y)} \, dy=1  \\  \\ \Rightarrow \int\limits^1_0 {cy} \, dy +\int\limits^2_1 {(2-y)} \, dy=1 \\  \\ \Rightarrow \left. \frac{cy^2}{2} \right]^1_0+\left[2y- \frac{y^2}{2} \right]^2_1=1 \\  \\ \Rightarrow  \frac{c}{2} +4-2-2+ \frac{1}{2} =1 \\  \\ \Rightarrow \frac{c}{2} = \frac{1}{2}  \\  \\ \Rightarrow \bold{c=1}



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