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3 years ago

For #1 and 2, Find the lateral area and surface area of each prism.

Mathematics

1 answer:

Veseljchak [2.6K]3 years ago

8 0

Answer:

1. Lateral: 72 SA: 142

2. SA: 36 Lateral: 24

Step-by-step explanation:

1. perimeter of base times the height

2l+2w x h

2(5) + 2(7) x 7

24 x 3 = 72

Surface area: A=2(wl+hl+hw)=2·(7·5+3·5+3·7)=142

2. Surface Area

Using the formulas

A=2AB+(a+b+c)h

AB=s(s﹣a)(s﹣b)(s﹣c)

s=a+b+c

Solving forA

A=ah+bh+ch+1

2﹣a4+2(ab)2+2(ac)2﹣b4+2(bc)2﹣c4=5·2+4·2+3·2+1

2·﹣54+2·(5·4)2+2·(5·3)2﹣44+2·(4·3)2﹣34

=36

Lateral: A=(a+b+c)h=(5+4+3)·2=24

You might be interested in

1/2(2g-3)=-4(g+1) show work

xz_007 [3.2K]

1/2(2g−3)=−4(g+1)
1/2(2g−3)=−4(g+1)
g+−3/2=−4g−4
g+−3/2+4g=−4g−4+4g5g+−32=−4
5g+−3/2+3/2=−4+3/2

5g=−5/2
5g/5=−525
g=−12

Hoped I helped!

5 0

3 years ago

You throw two four-sided dice. Let the random variable X represent the maximum value of the two dice. Compute E(X). Round your a

Troyanec [42]

Answer:

E(X)=3.125

Step-by-step explanation:

We are given that two four sided dice.

Then , the sample space

{(1,1),(1,2),(1,3),(1,4),(2,1),(2,2),(2,3),(2,4),(3,1),(3,2),(3,3),(3,4),(4,1),(4,2),(4,3),(4,4)}

Total number of outcomes=16

Let the random variable X represent the maximum value of the two dice

Outcomes X P(X)

(1,1) 1 1/16

(1,2),(2,1),(2,2) 2 3/16

(1,3),(2,3),(3,1),(3,2),(3,3) 3 5/16

(1,4),(3,4) ,(2,4),(4,1),(4,2),(4,3),(4,4) 4 7/16

Using the probability formula

$P(E)=\frac{Favorable\;outcomes}{Total\;number\;of\;outcomes}$

Now,

$E(X)=\sum_{i=1}^{n}x_iP(x_i)$

$E(x)=1(1/16)+2(3/16)+3(5/16)+4(7/16)$

$E(x)=\frac{1+6+15+28}{16}$

$E(x)=\frac{50}{16}=3.125$

7 0

3 years ago

Find the product. state your answer in standard form (x+7)(x squared + 6x - 8)

USPshnik [31]

Answer:

${x}^{3} + 13 {x}^{2} + 34x - 56$

Step-by-step explanation:

$(x + 7)( {x}^{2} + 6x - 8) \\ = x ( {x}^{2} + 6x - 8) + 7( {x}^{2} + 6x - 8) \\ = {x}^{3} + 6 {x}^{2} - 8x + 7 {x}^{2} + 42x - 56 \\ = {x}^{3} + 6 {x}^{2} + 7 {x}^{2} + 42x - 8x - 56 \\ = {x}^{3} + 13 {x}^{2} + 34x - 56 \\$

6 0

3 years ago

Read 2 more answers

Hey can you please help me posted picture of question

dolphi86 [110]

The larger the number of simulations the more likely are the results to be closest to those predicted by the probability theory.

When large number of simulations are run, some results might be higher than the results of probability theory, some results might be lower than the results of the probability theory and some might be exactly the same. So the average of all these results will be close to the results of Probability Theory. Thus, more the number of simulations, greater is the chance that the results are closer to those of simulation theory.

Thus, option A will be the correct answer.

4 0

2 years ago

Help me please guys.

Alex_Xolod [135]

15.04 degrees or answer A is correct.

The Law of Sines is the relationship between the sides and angles of non-right (oblique) triangles . Simply, it states that the ratio of the length of a side of a triangle to the sine of the angle opposite that side is the same for all sides and angles in a given triangle. The formula for it is A=b•sin a/sin b.

You can transform the law of sines formulas to solve some problems of triangulation (solving a triangle). You can use them to find:

The remaining sides of a triangle, knowing two angles and one side.
The third side of a triangle, knowing two sides and one of the non-enclosed angles. In some cases (ambiguous cases) there may be two solutions to the same triangle. If the following conditions are fulfilled, your triangle may be an ambiguous case:
You only know the angle α and sides a and c;
Angle α is acute (α < 90°);
a is shorter than c (a < c);
a is longer than the altitude h from angle β, where h = c * sin(α) (a > c * sin(α)).

I hate useless complicated math lol ;)

5 0

3 years ago