The answer is False!
P - dominant allele for inflated pods
p - recessive allele for inflated pods
PP - homozygote with inflated pods
Pp - heterozygote with inflated pods
pp - homozygote with inflated pods
S - dominant allele for round seeds
s - recessive allele for wrinkled seeds
SS - homozygote with round seeds
Ss - heterozygote with round seeds
ss - homozygote with wrinkled seeds
1. <span>A Pea plant that is homozygous for inflated pods are heterozygous for round seeds: PPSs
2. A</span><span> plant that is heterozygous for inflated pods and a homozygous for wrinkled seeds: Ppss
Let's look at their genotypes separately, and cross them that way:
Parents: PP x Pp
Offspring: PP PP Pp Pp
All of the offspring will have the same phenotype (100% = 1). So, this trait does not affect phenotypic ratio
</span>Parents: Ss x ss
Offspring: Ss Ss ss ss
Half of the offspring will have wrinkled seeds and half of them will have round seeds: 50% : 50% = 1 : 1
So, the phenotypic ratio is not 1 : 3
Answer:
D. service
Explanation:
Most people in the US work in jobs that require providing a service to others, whether it's at a restaurant, a department store, a school, etc. Yet, those who work in specialised jobs like agriculture, fishing, and mining are more rare because they need to live in a certain area that is optimal for such positions.
Thus, the answer is D.
Answer:
I think it's because it will decay and be soil and soil is biotic factor
Albert, a student researcher, varies the amount of food given to rats in an experiment to measure the effect on their learning behavior. In albert's study, the amount of food given is the independent variable.
An independent variable is under the control of the experimenter. Independent variable does not depend on the other variables involved in the experiment. Since the amount of food is varied, it is not depending on other variables like size of mice, weight, etc.
