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2 years ago

Suppose cos(O) = 5/13, Quadrant I. Find sin(O). A:13/12 B:12/13 C:13/5 D:5/12

Mathematics

1 answer:

Ne4ueva [31]2 years ago

8 0

Answer:

B. 12/13.

Step-by-step explanation:

Using the identity sin^2 O + cos^2 O = 1:

sin^2 O = 1 - cos^2 O

sin^2 O = 1 - (5/13)^2

= 1 - 25/169

= 169/169 - 25/169

= 144/169

So sin O = √(144/169)

= 12/13.

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A submarine dives 750 feet every 5 minutes and 4,500 feet every 30 minutes. Find the constant rate at which the submarine dives.

Anna35 [415]

Answer:

150 feet per minute

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3 years ago

The length of the hypotenuse of a right angled triangle exceeds the length of the base by 2cm and exceeds twice the length of th

insens350 [35]

Answer: a = 8; b = 15; c = 17

Step-by-step explanation:

c = b + 2 and c = 2a + 1

b = c − 2 and a = $\frac{c-1}{2}$

c² = b² + a²

$c^{2} = (c-2)^{2} + \frac{c-1}{2}\\$

$c^{2}= \frac{4 (c-2)^{2}+(c - 1)^{2} }{4}$

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$c^{2}-18c+17=0$

$c(c -17)-1(c-17)=0$

$(c -1)(c-17)=0$

c = 1 or c = 17

If c = 1 then b = 1 - 2 = -1, that's not possible

So x = 17

b = 17 - 2 = 15

a = $\frac{17-1}{2} = 8$

Length sides of the triangle are 17 cm, 15 cm and 8 cm.

I saw some of this on a site but I want to make sure its correct so we're gonna apply the pythagorean theory and see if its correct.

$a^{2} + b^{2} = c^{2} \\8^{2} + 15^{2} = 17^{2} \\64 + 225 = 289\\289 = 289\\$

This shows that this is correct.

Hope this helped! Again, some of this was from a site, not from me.

3 0

3 years ago

Slope: -1 intercept: -7.9

frosja888 [35]

Answer:

y = -x - 7.9

Step-by-step explanation:

Given:

m = -1

b = -7.9

y = mx + b

y = -x - 7.9

7 0

3 years ago

Read 2 more answers

Here’s the other one, i just need two more that i will be posting, ty your and amazing person

Anuta_ua [19.1K]

Answer:

See below.

Step-by-step explanation:

X-intercepts: (-7, 0) & (-3, 0)

Axis of Symmetry: x = -5

Y-intercept: (0, -21)

Vertex: (-5, 4)

4 0

3 years ago

A pet store sells goldfish and hermit crabs,

Elis [28]

Answer:

$Cost = \$28$

Step-by-step explanation:

Given

Represent Goldfish with g and hermit crabs with h.

The first statement, we have:

$7g + 3h = 26$

The second statement, we have:

$4g + 5h = 28$

Required

Determine the selling price of 6 goldfish and 4 hermit crabs

The equations are:

$7g + 3h = 26$ --- (1)

$4g + 5h = 28$ --- (2)

Make g the subject in (2)

$4g + 5h = 28$

$4g = 28 - 5h$

Divide both sides by 4

$g = \frac{1}{4}(28 - 5h)$

Substitute $\frac{1}{4}(28 - 5h)$ for g in (1)

$7g + 3h = 26$

$7(\frac{1}{4}(28 - 5h)) + 3h = 26$

$\frac{7}{4}(28 - 5h) + 3h = 26$

Multiply through by 4

$4 * \frac{7}{4}(28 - 5h) + 4*3h = 26*4$

$7(28 - 5h) + 4*3h = 26*4$

Open bracket

$196 - 35h + 12h = 104$

$196 -23h = 104$

Collect Like Terms

$-23h = 104-196$

$-23h = -92$

Make h the subject

$h = \frac{-92}{-23}$

$h = \frac{92}{23}$

$h = 4$

Substitute 4 for h in $g = \frac{1}{4}(28 - 5h)$

$g = \frac{1}{4}(28 - 5*4)$

$g = \frac{1}{4}(28 - 20)$

$g = \frac{1}{4}(8)$

$g = 2$

This implies that:

1 goldfish = $2

1 hermit crab = $4

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$Cost = 6g + 4h$

$Cost = 6*\$2 + 4*\$4$

$Cost = \$12 + \$16$

$Cost = \$28$

5 0

3 years ago