Answer:
-2x-2y-2z I think that is answer
We need to use the variables m and n to represent both numbers.
Their sum must equal -15. Therefore, we can write the next equation:
m + n = -15
If one number is five less than the other, we need to choose one variable and then we can write it in terms of the other variable. Then:
n = m-5
To find the value for each number, we can replace the n equation on the first equation:
m + n = -15
m + (m-5)= -15
Then:
m + m - 5 = -15
2m -5 = -15
Solve the equation for m:
Add both sides 5 units:
2m - 5 +5 = -15+5
2m = -10
Divide both sides by 2:
2m/2 = -10/2
m = -5
Finally, replace the m value on the first equation:
m + n = -15
-5 + n = -15
Then, solve the equation for n:
Add both sides by 5:
-5+5 + n = -15 +5
n = -10
Hence, both numbers are m=-5 and n= -10.
The equations separated by a comma are m + n = -15,n = m-5.
The numbers separated by a comma are -5,-10.
The lowest terms for 19/31 would be 1
Answer:
4 units count the boxes from a to b and that's 4
Answer:
2/3a^5
Step-by-step explanation:
we know that 2/7x2/7x2/7 = 8/27
a^15 cube will be a^5
because we know (2^3)^2 = 2^6
so (a^5)^3 = a^15
2/3a^5
