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Svetach [21]
3 years ago
12

Please tell me the final answer to this question and the process. Thanks!

Mathematics
1 answer:
shusha [124]3 years ago
3 0
There are two triangles that are 15cm in height and 10cm in width so you do 15 times 10 which is 150 then divided it by 2 because it a triangle to get 75 then because there is 2 you then multiply it by 2 again and you get 150
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What are the like terms in the expression<br>below?<br><br>3x + 8 + 3y + 8x​
Lorico [155]
The like terms would be 3x and 8x
4 0
3 years ago
What is the difference of a number s and 6 an expression
kow [346]
What is the word problem?

8 0
3 years ago
Read 2 more answers
Which equation represents the line that passes through (–6, 7) and (–3, 6)?
ipn [44]

Answer:

y = \frac{-x}{3} + 5

Step-by-step explanation:

Given A (x₁, y₁) = ( -6, 7) and B (x₂, y₂) = (-3, 6)

Slope of line passing through points ( -6, 7) and  (-3, 6) is:

m = \frac{y_{2} -y_{1}}{x_{2} -x_{1}} =\frac{6 - 7}{-3 + 6} =\frac{-1}{3}

Now, the equation of line in point-slope form:

(y - y₁) = m (x - x₁)

Substituting the value of m and  (x₁, y₁) = ( -6, 7) in above equation,

(y - 7) = \frac{-1}{3}(x - (-6))

(y - 7) = \frac{-1}{3}(x + 6)

3y - 21 = -x - 6

3y = -x - 6 + 21

3y = -x + 15

y = \frac{-x + 15}{3}

y = \frac{-x}{3} + 5

Option B is the correct answer.

6 0
2 years ago
Read 2 more answers
Perform the indicated operation and express the result as a simplified complex number. I need help with 35
skelet666 [1.2K]

Given:-

\frac{3+4i}{2-i}

To find:-

The simplified form.

At first we take conjucate and multiply below and above.

The conjucate is,

2+i

So now we multiply. we get,

\frac{3+4i}{2-i}\times\frac{2+i}{2+i}

Now we simplify. so we get,

\frac{3+4i}{2-i}\times\frac{2+i}{2+i}=\frac{6+3i+8i+4(i)^2}{2^2-i^2}

We know the value of,

i^2=-1

Substituting the value -1. we get,

\begin{gathered} \frac{6+3i+8i+4(i)^2}{2^2-i^2}=\frac{6+3i+8i+4(-1)_{}^{}}{2^2-(-1)^{}} \\ \text{                               =}\frac{6-4+11i}{2+1} \\ \text{                              =}\frac{2+11i}{3} \end{gathered}

So now we split the term to bring it into the form a+ib. so we get,

\frac{2+11i}{3}=\frac{2}{3}+i\frac{11}{3}

So the required solution is,

\frac{2}{3}+i\frac{11}{3}

3 0
1 year ago
What is the domain of f?
lana [24]

Answer: C) All real values of x such that x \le 0

In other words, x must be 0 or smaller.

===================================================

Explanation:

The reason why is because we must make the stuff under the square root to never be negative. We must make -2x be 0 or larger.

So,

-2x \ge 0 \\\\-2x+2x \ge 0+2x \ \text{ ... add 2x to both sides}\\\\0 \ge 2x\\\\2x \le 0  \ \text{ ... flip both sides, and the inequality sign}\\\\x \le 0/2  \ \text{ ... divide both sides by 2}\\\\x \le 0

As an example, if x = -2, then -2x = -2(-2) = 4 is positive. Applying the square root to a positive number is valid.

But if x = 5, then -2x = -2*5 = -10 is under the square root, which is not allowed.

3 0
2 years ago
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