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3 years ago

5.49 EE14

Mathematics

1 answer:

m_a_m_a [10]3 years ago

6 0

Answer:

5.555.5 im pretty sure

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Which equation can be used to find 42 x 51?

Marizza181 [45]

Answer:

(40 x 50) + (40 x 1) + (2 x 50) + (2 x 1) = 2,000 + 40 + 100 + 2

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3 years ago

Read 2 more answers

Answer the questions for 9 points and brainliest <br> What is the median of the data

Marizza181 [45]

Answer:

Step-by-step explanation:

The median is the line in the middle of the box

40 is the median

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3 years ago

Marco starts getting ready for soccer practice at 3:55 P.M. if it takes him 15 minutes to get ready, what time is he ready to le

IceJOKER [234]

Answer:

4:10 PM

Step-by-step explanation:

15 minutes can be slit into 5 minutes and 10 minutes

There are 60 minutes in an hour!

3:55 + 0:05 = 4:00

4:00 + 0:10 = 4:10

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2 years ago

What is this percent of change 40;72

salantis [7]

Given:
Original or base : 40
New amount : 72

We need to find the difference of the new amount and the original amount

72 - 40 = 32

We then divide the difference by the original amount

32/40 = 0.80

We multiply the quotient by 100%

0.80 x 100% = 80%

The percentage of change is 80%

6 0

3 years ago

A filter filled with liquid is in the shape of a vertex-down cone with a height of 9 inches and a diameter of 6 inches at its op

Alina [70]

Answer: Level of the liquid dropping at 28.28 inch/second when the liquid is 2 inches deep.

Step-by-step explanation:

Since we have given that

Height = 9 inches

Diameter = 6 inches

Radius = 3 inches

So, $\dfrac{r}{h}=\dfrac{3}{9}=\dfrac{1}{3}\\\\r=\dfrac{1}{3}h$

Volume of cone is given by

$V=\dfrac{1}{3}\pi r^2h\\\\V=\dfrac{1}{3}\pi \dfrac{1}{9}h^2\times h\\\\V=\dfrac{1}{27}\pi h^3$

By differentiating with respect to time t, we get that

$\dfrac{dv}{dt}=\dfrac{1}{27}\pi \times 3\times h^2\dfrac{dh}{dt}=\dfrac{1}{9}\pi h^2\dfrac{dh}{dt}$

Now, the liquid drips out the bottom of the filter at the constant rate of 4 cubic inches per second, ie $\dfrac{dv}{dt}=-4\ in^3$

and h = 2 inches deep.

$-4=\dfrac{1}{9}\times \pi\times (2)^2\dfrac{dh}{dt}\\\\-9\pi =\dfrac{dh}{dt}\\\\-28.28=\dfrac{dh}{dt}$

Hence, level of the liquid dropping at 28.28 inch/second when the liquid is 2 inches deep.

7 0

2 years ago