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3 years ago

Find the missing side lengths. Leave your answers as radicals in simplest form

Mathematics

1 answer:

tino4ka555 [31]3 years ago

6 0

We have the triangle 30° - 60° - 90°.

The lenght of the sides are in proportion: $1:2:\sqrt3\to a:2a:a\sqrt3$

$a=y\\2a=x\\a\sqrt3=5\\\\a\sqrt3=5\qquad\text{multiply both sides by}\ \sqrt3\\\\3a=5\sqrt3\qquad\text{divide both sides by 3}\\\\a=\dfrac{5\sqrt3}{3}\\\\2a=2\cdot\dfrac{5\sqrt3}{3}=\dfrac{10\sqrt3}{3}\\\\Answer:\ x=\dfrac{10\sqrt3}{3},\ y=\dfrac{5\sqrt3}{3}$

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700000x800000000 what is equivalent to 6x+9+-6

Ostrovityanka [42]

Answer:

If you're trying to evaluate 6x + 9 + (-6), then the answer would be ↓

Step-by-step explanation:

6x + 3

6 0

2 years ago

Help please........

german

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3 years ago

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3 years ago

Heather has divided $5400 between two investments, one paying 8%, the other paying 5%. if the return on her investment is $

Phantasy [73]

Answer:

$2500 at 8%.

$2900 st 5%.

Step-by-step explanation:

Let x be the amount invested at rate of 8% and y be the amount invested at the rate of 5%.

We have been given that Heather has divided $5400 between two investments. We can represent this information as:

$x+y=5400...(1)$

The return on her investment is $345.

Earnings from the investment at 8% will be 8% of x.

Earnings from the investment at 5% will be 5% of y.

$(\frac{8}{100})x+(\frac{5}{100})y=345...(2)$

$0.08x+0.05y=345...(2)$

We will use substitution method to solve our system of equations. From equation (1) we will get,

$x=5400-y$

Substituting this value in equation (2) we will get,

$0.08(5400-y)+0.05y=345$

$432-0.08y+0.05y=345$

$-0.08y+0.05y=345-432$

$-0.03y=-87$

$\frac{-0.03y}{-0.03}=\frac{-87}{-0.03}$

$y=2900$

Therefore, Heather has invested an amount of $2900 at 5%.

Let us substitute y=2900 in equation (1) to solve for x.

$x+2900=5400$

$x+2900-2900=5400-2900$

$x=2500$

Therefore, Heather has invested an amount of $2500 at 8%.

6 0

3 years ago

students were grouped into 4 classrooms with an average of 33.5 students per classroom. if the students were regrouped into 5 cl

erma4kov [3.2K]

Answer:

26.8

Step-by-step explanation:

Because 33.5 was the average of how many students were in a classroom (if there were 4 classrooms), then 33.5 is can somewhat be the average of how many students were in one classroom; 1/4 of the classrooms can hold an average of 33.5.

Total students that were divided into 4 classrooms :

33.5 × 4 = 134

So if there is 134 students that will be grouped into 5 different classrooms, divide 134 by 5 to find the average amount of students that will be grouped.

134 ÷ 5 = 26.8

So, the average amount of students that will be grouped if they were divided into 5 classrooms would be 26.8 .

Hope this helped !

4 0

2 years ago