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asambeis [7]
3 years ago
10

Could someone help plz

Mathematics
1 answer:
Murrr4er [49]3 years ago
4 0
I think compatible numbers
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PLEASE SOMEONE HELP ME
evablogger [386]

Answer:

What grade is this question?

Step-by-step explanation:

in a momment im in class

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3 years ago
15 pionts and brainllest to first answer unless wrong please halp asap
Galina-37 [17]

Answer:

area of semicircle only = 113.43 mm²

total area = 185.43 mm²

Step-by-step explanation:

(8.5²)(π)(0.5) = 113.43 mm²

(12)(12)(.5) = 72 mm²

72 + 113.43 = 185.43 mm²

5 0
2 years ago
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The average distance from the sun to Venus is 67,237,910 miles. The average distance from the sun to earth is 92,955,807 miles
murzikaleks [220]
Find the difference, so subtract the two and you should get the answer from earth to Venus
3 0
3 years ago
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Find the volume of the cone 3ft and 2 ft. Round your answer to the nearest tenth if necessary. Use 3.14 for pie
denpristay [2]

Answer:

37.68 ft^3

Step-by-step explanation:

The parameters used in describing a cone is radius and height

Hence

Radius= 3ft

Height = 2 ft

The volume of a cone is given as

v=\frac{1}{3} \pi r^2 h

substitute

v=\frac{1}{3}*3.14*3^2*2^2\\\\v=\frac{1}{3}*3.14*9*4\\\\v=\frac{1}{3}*113.04\\\\v=37.68 ft^3

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5 0
3 years ago
I NEED HELP AND IM ON A TIMED TEST
stira [4]

This Question is not Complete

Complete question

The number of absences per student in each of two classes is shown on the dot plots below.

A dot plot titled Number of absences per student in Misses Anderson's class. The number line goes from 0 to 6. There is 1 dot above 0, 3 above 1, 3 above 2, 3 above 3, 1 above 4, and 0 above 5 and 6.

A dot plot titled Number of absences per student in Misses Bergot's class. The number line goes from 0 to 6. There is 1 dot above 0, 1 above 1, 2 above 2, 3 above 3, 2 above 4, 1 above 5, and 1 above 6.

Which statements accurately compare the two data sets? Select three options.

a. The mean number of absences is greater in Mrs. Anderson’s class.

b. The mean number of absences is greater in Mrs. Bergot’s class.

c. There is more variability in Mrs. Anderson’s data set.

d. There is more variability in Mrs. Bergot’s data set.

e. The mean and MAD are better representations of these data sets than the median and IQR.

Answer:

b. The mean number of absences is greater in Mrs. Bergot’s class.

d. There is more variability in Mrs. Bergot’s data set.

e. The mean and MAD are better representations of these data sets than the median and IQR.

Step-by-step explanation:

From the above data given in the question and the options given to us, we can observe from the comparison of both the number of absences in Mrs Bergot's class to that in Mrs Anderson's class, there will be a presence of variation in the data of one of the classes and that class happens to be Mrs Bergot's class.

The appropriate statistical tool that we can be used to determine and measure the centre of variability of the data is Mean and Mean Absolute Deviation.

7 0
3 years ago
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