What is the equation of the line that passes through (4, -1) and (-2, 3)?
2 answers:
Answer:
2x+3y-5=0
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(3-(-1))/(-2-4)
m=(3+1)/-6
m=4/-6
simplify
m=-2/3
y-y1=m(x-x1)
y-(-1)=-2/3(x-4)
y+1=-2/3x+8/3
y=-2/3x+8/3-1
y=-2/3x+8/3-3/3
y=-2/3x+5/3
y-(-2/3x)=5/3
y+2/3x=5/3
3(y+2/3x)=3(5/3)
3y+6/3x=15/3
3y+2x=5
2x+3y=5
2x+3y-5=0
Answer:
2x + 3y - 5 = 0
Step-by-step explanation:
hello :
(4;-1) : x=4 and y = -1 so : 2(4)+3(-1)-5 = 0 means : 8-3-5 =0...true
(-2;3) : x=-2 and y = 3 so : 2(-2)+3(3)-5 = 0 means : -4+9-5 =0...true
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