9514 1404 393
Answer:
a) x = -3
b) y = (28/27)x -27
Step-by-step explanation:
a) College street has a slope of 0, so is a horizontal line. 2nd Ave is perpendicular, so is a vertical line, described by an equation of the form ...
x = constant
For 2nd Ave to intersect the point (-3, 1), the constant must match that x-coordinate. The equation is ...
x = -3
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b) Since Ace Rd is perpendicular to Davidson St, its slope will be the opposite reciprocal of the slope of Davidson St. The slope of Ace Rd is ...
m = -1/(-27/28) = 28/27
Using the point-slope equation for a line, we can model Ace Rd as ...
y -y1 = m(x -x1)
y -1 = (28/27)(x -27)
y = (28/27)x -27
Bc. log a - log b = log (a/b) than use this formula will get
log x^2 -log x = log (x^2 /x) = log x so choice D. is right sure
hope helped
Answer:
So..how was the test?
Step-by-step explanation:
Did you pass???
Root of 49
Solutions are 7 and -7
We know that 7 is the square root of 49.
A negative number multiplied by itself gives positive
So -7 is also a square root of 49