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3 years ago

What is always true about a line that slants downward from left to right

Mathematics

1 answer:

Advocard [28]3 years ago

8 0

Answer:

12 x 12+144

Step-by-step explanation:

You might be interested in

Find the value of x . 12.5,−10,−7.5,x ; The mean is 11.5 .

fomenos

There are four values, including the unknown value x. The sum of the four values is the given value of the mean, 11.5, multiplied by four. Let S be the sum of the four values. Then we can write:
$S=11.5\times4=46$

$46=12.5 + (-10)+(-7.5)+x$
x = 46 + 5 = 51
The answer is: The value of x is 51.

4 0

4 years ago

I need some help with this math problem

gizmo_the_mogwai [7]

Step-by-step explanation:

15 long

12 wide

10 high

we need all for walls

hight times length two times ( these are the front and back walls )

hight times width two times ( These are the side walls )

the roof is

width times length (only once as only the ceiling)

same measurement as the floor

can you work it out with that

please mark brainiest

8 0

3 years ago

Shawntee has 21 coins all of them nickel and dimes that are worth $1.70. Write a system of equations and splve

Kipish [7]

N+d=21
5n+10d=170

so

multiply first equation by -5 and add to other one

-5n-5d=-105
5n+10d=170 +
0n+5d=65

5d=65
divide both sides by 5
d=13

sub back

n+d=21
n+13=21
minus 13 both sides
n=8

8nickles
13 dimes

8 0

3 years ago

Find a point on the y-axis that is equidistant from the points (8, −8) and (1, 1).

artcher [175]

$\text{We know that any point on the y-axis is of the form (0, y),}\\
\text{because on y-axis we have x=0.}\\
\\
\text{So let (0, y) be the point on the y-axis that is equidistance from}\\
\text{the points }(8,-8) \text{ and }(1,1)\\
\\
\text{so using the distance formula, we have}\\
\\
\text{Distance between (0, y) and }(8,-8)=\text{Distance between (0,y) and }(1,1)\\
\\
\Rightarrow \sqrt{(0-8)^2+(y-(-8))^2}=\sqrt{(0-1)^2+(y-1)^2}$

$\Rightarrow \sqrt{64+(y+8)^2}=\sqrt{1+(y-1)^2}\\
\\
\text{Squaring both sides, we get}\\
\\
(\sqrt{64+(y+8)^2})^2=(\sqrt{1+(y-1)^2})^2\\
\\
\Rightarrow 64+(y+8)^2=1+(y-1)^2\\
\\
\Rightarrow 64+(y^2+16y+64)=1+(y^2-2y+1)\\
\\
\Rightarrow y^2+16y+128=y^2-2y+2\\
\\
\Rightarrow y^2+16y-y^2+2y=2-128\\
\\
\Rightarrow 18y=-126\\
\\
\Rightarrow y=\frac{-126}{18}\\
\\
\Rightarrow y=-7$

So the point on the y-axis that is equidistant from the points (8,-8) and (1,1) is: (0,-7)

3 0

4 years ago

Need help ASAPPPPPPP

patriot [66]

Answer:

8 is the correct answer because coefficient lies before Exponent. Exponent is variable

So 8 is the coefficient.

5 0

3 years ago