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3 years ago

If you were to roll the dice one time, what is the probability it will land on a 2?

Mathematics

2 answers:

vladimir2022 [97]3 years ago

6 0

Answer:

1 out of 6

Step-by-step explanation:

tiny-mole [99]3 years ago

4 0

<h3>♫ :::::::::::::::::::::::::::::: // Hello There ! // :::::::::::::::::::::::::::::: ♫</h3>

➷ There is only one '2' on the dice

The total amount of numbers of the dice is 6

The probability would be : amount of desired outcome / total outcomes

Thus, the probability would be 1/6.

[any further queries, feel free to ask]

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

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Answer:

the answer is 9

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2 years ago

26) Write the equation of the circle with center (0, 0) and (3, 6) a point on the circle. A) x2 + y2 = 9 B) x2 + y2 = 30 C) x2 +

alexdok [17]

Answer:C) x2 + y2 =45

Step-by-step explanation:

The equation of a circle in standard form is (x-h)2+(y-k)2=r2.

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4 0

3 years ago

Read 2 more answers

Molly was on a long 136 mile road trip. The first part of the trip there was lots of traffic, she only averaged 16 mph. The seco

Mazyrski [523]

Answer:

In traffic, she drove for 3 hours

and After the traffic cleared she drove for 2 hours.

Explanation:

Given that the road trip was 136 miles;

$d=136$

The first part of the trip there was lots of traffic, she only averaged 16 mph;

$v_1=16$

The second part of the trip there was no traffic so she could drive 44 mph;

$v_2=44$

She traveled for a total of 5 hours;

$t=5$

let x represent the time in traffic when she traveled at 16 mph

$t_1=x$

the time the traffic is clear would be;

$t_2=t-t_1=5-x$

Recall that distance equals speed multiply by time;

$d=v_1t_1_{}_{}^{}+v_2t_2$

substituting the values;

$136=16x+44(5-x)$

solving for x;

$\begin{gathered} 136=16x+220-44x \\ 44x-16x=220-136 \\ 28x=84 \\ x=\frac{84}{28} \\ x=3 \end{gathered}$

So;

$\begin{gathered} t_1=3\text{ hours} \\ t_2=5-x=5-3=2 \\ t_2=2\text{ hours} \end{gathered}$

Therefore, In traffic, she drove for 3 hours

and After the traffic cleared she drove for 2 hours.

7 0

2 years ago

F(t)=t^2+19t+60<br> What are the zeros of the function and what is the vertex of the parabola?

SVEN [57.7K]

Answer: $-4,-15;\ \left(-\dfrac{19}{2},-\dfrac{121}{4}\right)$

Step-by-step explanation:

Given

Function is $F(t)=t^2+19+60$

Zeroes of the function are

$t^2+19t+60=0\\\\\Rightarrow t=\dfrac{-19\pm\sqrt{19^2-4\times 1\times 60}}{2\times 1}\\\\\Rightarrow t=\dfrac{-19\pm \sqrt{121}}{2}\\\\\Rightarrow t=\dfrac{-19\pm 11}{2}\\\\\Rightarrow t=-4,-15$

Using completing the square method

$y=t^2+2\times \dfrac{19}{2}t+\dfrac{19^2}{2^2}-\dfrac{19^2}{2^2}+60\\\\y=\left(t+\dfrac{19}{2}\right)^2+60-\dfrac{361}{4}\\\\y=\left(t+\dfrac{19}{2}\right)^2-\dfrac{121}{4}\\\\y+\dfrac{121}{4}=\left(t+\dfrac{19}{2}\right)^2\\\\\left(y-(-\dfrac{121}{4}\right)=\left(t-(-\dfrac{19}{2})\right)^2\\\\\text{The vertex is }\left(-\dfrac{19}{2},-\dfrac{121}{4}\right)$

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3 years ago