1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
pishuonlain [190]
3 years ago
9

Two numbers have a ratio of 4 to 5 and the sum of the numbers is 108 what are the two numbers??

Mathematics
1 answer:
ipn [44]3 years ago
8 0

Answer: 48,60

Step-by-step explanation:

4x+5x=108

9x=108

x=108/9=12

12•4=48

12•5=60

You might be interested in
PLEASE HELP NOW!! If K is the set of all letters in the word “equation”, and L is the set of all letters of the word “inequality
satela [25.4K]

Answer:

e,q,u,a,t,i,n & EQUATIONYL

Step-by-step explanation:

K∩L:

First write both the words, equation and inequality down.

E Q U A T I O N

I N E Q U A L I T Y

You can see EQUATIN repeats in both of the words.

K∪L:

First write both the words, equation and inequality down.

E Q U A T I O N

I N E Q U A L I T Y

This time just write down all the letters EXCEPT the ones that repeat. EQUATIONYL

6 0
2 years ago
Find the value of C that completes the square
MatroZZZ [7]

Answer:

Step-by-step explanation:

y^2-22y+c

complete the square ax^2+bx+c is our old formula quadratic equation

we know that to find c we will divide b/2 and square it

22/2=11

c^2=121

we have y^2-22y+121

6 0
3 years ago
Which could be the first step in simplifying this expression? Check all that apply. (x cubed x Superscript negative 6 Baseline)
PtichkaEL [24]

Answer:

(x^{-3} )^{2}

x^6 x^{-12}

Step-by-step explanation:

(x^{3} x^{-6} )^{2} is the expression given to be solved.

First of all let us have a look at <u>3 formulas</u>:

1.\ p^a \times p^b = p^{(a+b)}\\2.\ (p^a \times q^b)^c = (p^{a})^c \times (q^{b})^c\\3.\ (p^a)^b = p^{a\times b}

Both the formula can be applied to the expression((x^{3} x^{-6} )^{2}) during the first step while solving it.

<u>Applying formula (1):</u>

(x^{3} x^{-6} )^{2}

Comparing the terms of (x^{3} x^{-6} ) with p^a \times p^b

p=x, a =3, b=-6

\Rightarrow x^{3+(-6)}\\\Rightarrow x^{3-6}\\\Rightarrow x^{-3}

So, (x^{3} x^{-6} )^{2} is reduced to (x^{-3} )^{2}

<u>Applying formula (2):</u>

Comparing the terms of (x^{3} x^{-6} )^{2} with (p^a \times q^b)^c

p=q=x, a =3, b=-6, c=2

\Rightarrow (x^{3})^2\times (x^{-6})^2\\\text{Applying Formula (3)}\\x^6 x^{-12}

So, (x^{3} x^{-6} )^{2} is reduced to x^6 x^{-12}.

So, the answers can be:

(x^{-3} )^{2}

x^6 x^{-12}

8 0
2 years ago
What is 0.012 in percent?
stepan [7]

Answer:

1.2%

Step-by-step explanation:

0.012 = 12/1000

to express it as %

12/1000 * 100

= 1.2%

7 0
2 years ago
Read 2 more answers
What is the relationship between sin(90 degrees) and sin(-90 degrees)
Volgvan

Answer:

sin(90\°)=-sin(-90\°)

Step-by-step explanation:

we know that

sin(90\°)=1

sin(-90\°)=-1

therefore

sin(90\°)=-sin(-90\°)

4 0
3 years ago
Other questions:
  • Solve. 3 |x-8| =3 <br> A.) x = 9 or x = 7 <br> B.) x = 11 <br> C.) x = 9 <br> D.) x = 11 or x = 5
    14·1 answer
  • PLEASE HELP?!
    7·1 answer
  • 7. Find the measure of one exterior angle of<br><br> the regular polygon.<br><br> Triangle
    14·1 answer
  • What is 1/4 of 32 PLEASE HELP ME IM STUCK
    5·2 answers
  • What is the equation of the line that passes through (4, 2) and is parallel to 3x – 2y = –6?
    11·2 answers
  • What is the difference between supplementary and complementary angles?
    12·2 answers
  • If you multiply 50x50 will you always get the right answer
    12·1 answer
  • IN the 30-60-90 triangle below, side s has a length of ? and side q has a length of ?
    6·1 answer
  • a person is scheduled to pick up 9 crates each crate weighs 1/4 how much weight will the delivery have
    9·2 answers
  • Compare investing $1500 at 9% compounded monthly for 11 years with investing $1500 at 14% compounded monthly for 11 years.
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!