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ANTONII [103]
2 years ago
7

Terry and bob each have an aquarium Terry’s aquarium is 14 cm long 12 cm high and 10 cm wide bobs aquarium is 13 cm long 15 cm h

igh and wide who’s aquarium holds the larger volume of water explain how you know
Mathematics
2 answers:
lozanna [386]2 years ago
6 0

Answer:

I know its bobs but idk how to explain

Step-by-step explanation:

skelet666 [1.2K]2 years ago
4 0
Bob’s aquarium can hold more.

The formula for volume is Length x Width x Hight. Using that formula you get 1680cm2 for Terry’s and 2925cm2 for Bob’s.
You might be interested in
Am i correct?? <br><br>-- &gt; if i am wrong. show details on why.
Anna35 [415]

Answer:

Sorry to say that you are wrong,it should be the last choice

NP of the first triangle is 36,and it touches MP,and 36 is bigger than 33.Although it looks like same,it is not really the same.

Hope that helps.:)

8 0
3 years ago
Read 2 more answers
What is the value of 4*(-1+2-3+4-3+6-7+....+100) Show your work. [Pls help I am really drowning in work. 50 points + brainliest
KengaRu [80]

Answer:

200

Step-by-step explanation:

We have:

4(-1+2-3+4-5+6-7...+100)

We can rearrange the numbers to obtain:

4((-1-3-5-7-...-99)+(2+4+6...+100))

From the left, we can factor out a negative. So:

4(-(1+3+5+7+...+99)+(2+4+6...+100))

In other words, we want to find the sum of all the odd numbers from 1 to 99.

And the sum of all the even numbers from 2 to 100.

Let's do each one individually:

Odd Terms:

We have:

(1+3+5+7+...+99)

We can use the arithmetic series formula, where:

S=\frac{k}{2}(a+x_k)

Where k is the number of terms, a is the first term, and x_k is the last term.

Since it's all the odd numbers between 1 and 99, there are 50 terms.

Our first term is 1 and our last term is 99. So, the sum of all the odd terms are:

S=\frac{50}{2}(1+99})

Divide the fraction. Add within the parentheses:

S=25(100)

Multiply:

S=2500

So, the sum of all the odd terms is 2500.

Even Terms:

We have:

(2+4+6+...+100)

Again, we can use the above formula.

Our first term is 2, last term is 100. And since it's from 2-100, we have 50 even terms. So:

S=\frac{50}{2}(2+100)

Divide and add:

S=25(102)

Multiply:

S=2550

We originally had:

4(-(1+3+5+7+...+99)+(2+4+6...+100))

Substitute them for their respective sums:

4(-(2500)+2550)

Multiply:

4(-2500+2550)

Add:

=4(50)

Multiply:

=200

So, the sum of our sequence is 200.

And we're done!

Note: I just found a <em>way</em> easier way to do this. We have:

4\cdot(-1+2-3+4-5+6-7+...+100)

Let's group every two terms together. So:

=4((-1+2)+(-3+4)+(-5+6)...+(-99+100))

We can see that they each sum to 1:

=4((1)+(1)+(1)+...+(1))

Since there are 100 terms, we will have 50 pairs, so 50 times 1. So:

=4(50)

Multiply:

=200

Pick which one you want to use! I will suggest this one though...

Edit: Typo

8 0
3 years ago
Kris and Julio played a card game.Together they scored 36 points in one game.Kris scored 2 times as many points as julio.How man
sergejj [24]
Try this option:
1. according to the condition Kris scored '2x' points, Julio did 'x' points (Kris scored 2 times as many points as Julio).
2. according to the condition Kris'_points+Julio's_points=36_points. It means, that x+2x=36.
3. If to solve this equation (2x+x=36), then Julio scored x=12 points, Kris scored 2x=12*2=24 points.

answer: 12 (Julio); 24 (Kris).
6 0
3 years ago
WIll give brainliest Use the information given to answer the question.
MaRussiya [10]

Answer:

x²-12x+36

Step-by-step explanation:

an expression in the form (a-b)² is expanded to the form a²-2ab+b²

you can also expand it to (x-6)×(x-6) then multiply the first term by the first the outer term by the outer term the inner term by the inner term and the last term by the last term (foil)

the first terms are x and x = x² the outer terms are x and -6 = -6x the inner terms are also x and -6 = -6x

the last terms are 6 and 6 = 36

adding all the four products =

x²-12x+36

7 0
3 years ago
Assume that 200 babies are born to 200 couples treated with the XSORT method of gender selection that is claimed to make girls m
JulsSmile [24]

Answer:

a) test statistic = 2.12

b) p-value = 0.017

c) we reject the Null hypothesis

Step-by-step explanation:

Given data :

N = 200

girls (x) = 115 , Boys = 85

p = x / n = 115 / 200 = 0.575

significance level ( ∝ ) = 0.1

<em>aim : test whether the proportion of girls births after the treatment is greater than 50% that occurs without any treatment </em>.

<u>A) Determine the test statistic </u>

H0 : p = 0.5

Ha : p > 0.5

to determine the test statistic we will apply the z distribution at ( ∝ ) = 0.1

Z - test statistic = ( 0.575 - 0.5)  / \sqrt{0.5*0.5 / 200}  = 2.12

<u>b) determine the p-value</u>

The P-value can be determined using the normal standard table

P-value = 1 - p(Z< 2.12 )  =  1 - 0.9830 = 0.017

c) Given that the p value ( 0.017 ) < significance level ( 0.1 )

we will reject the H0 because there is evidence showing that proportion of girls birth is > 50%

3 0
3 years ago
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