Answer:
dV = - 5.73*10⁹ m³/s
Step-by-step explanation:
Question: What is the rate of change of the volume of the prism at that instant (in cubic meters per second) ?
A function can be dependent on one or more variables. The change in the function due to a change in one o its variables is given by the functions derivative with respect to that variable. For functions that are composed of products of its variables, we may use the product rule to determine its derivative.
The volume of a square prism with base a and height h is given by
V = a²h
When the base and height are changing, we have
dV = 2ah(da/dt) + a²(dh/dt)
Given
a = 4 Km
h = 9 Km
da/dt = - 7 Km/min
dh/dt = 10 Km/min
we have
dV = 2(4 Km)(9 Km)(- 7 Km/min) + (4 Km)²(10 Km/min)
⇒ dV = - 504 Km³/min + 160 Km³/min = - 344 Km³/min
⇒ dV = - 5.73*10⁹ m³/s
Answer:
it is a it shows 19 is n and is smaller than 23
Answer:
All units of measurement that are not based on or do not measure mass or weight and volume are incommensurable with kilograms.
Step-by-step explanation:
A measure unit is said to be incommensurable with another if it does not have the same measurement basis with the other measure unit. For example, a measure in time cannot be measured in kilograms because time is measured in hours, minutes, seconds, days, etc. But, if a measurement base can be applied to two or more measurement units, then the measurement units are commensurable with the measurement base.
