Hi there!
200(20)^x > 500x + 400
Let's find the critical points of the inequality
200(20^x) = 500x + 400
Now we can divide both sides by 200
(200(20^x))/200 = (500x + 400)/200
20x^x = 5/2 x + 2
There are no critical points.
Thus,
The answer is: No solution
As always, it is my pleasure to help students like you.
Answer:
2 I think
Step-by-step explanation:
B= number of beakers which there are 450
t= number of test tubes
the answer is 1.46
If 32 is divided by 6, the answer is 5.3. However because she cannot hit part of a ball, the number would be 5. Therefore, she would hit 5 out of 32 balls.
Answer:
Step-by-step explanation:
Let X= each ticket for adults and Y= each ticket for kids
x+y=548
6.50x+3.50y=2881
subtract x from each side leaving you with y= -x+548
Plug in for Y
6.50x+3.50(-x+548)=2881
6.50x - 3.50x + 1918= 2881
3x+1918=2881 ....subtract
3x=963 .....divide by 3
X= 321 tickets for adults
321+y=548 ...subtract 321
Y=227 childrens tickets