If <em>x</em> is the smallest of the three, then the next two integers are <em>x</em> + 2 and <em>x</em> + 4.
"Twice the largest is 20 less than the sum of all three" translates to
2 (<em>x</em> + 4) = (<em>x</em> + (<em>x</em> + 4) + (<em>x</em> + 6)) - 20
Solve for <em>x</em> :
2<em>x</em> + 8 = 3<em>x</em> - 10
<em>x</em> = 18
Then the three numbers are {18, 20, 22}.
In the secant secant theorem,
AP × BP = CP × DP
AP × 6 = 7 × 12
AP = 7 × 2 = 14
Answer: 14
An=-31+(n-1)-11 find the eleventh term
a11 = -31 + (-11) (11-1)
a11 = -31 +-11(10)
a11 =-31 +-110
a11 = -142
Answer:
32,000
Step-by-step explanation: