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lakkis [162]
3 years ago
15

Name the intersection of plane BPQ and plane CPQ.

Mathematics
2 answers:
Likurg_2 [28]3 years ago
7 0

The intersection of plane BPQ and plane CPQ is <u>line PQ</u>.

alexandr1967 [171]3 years ago
4 0

Answer:

the intersection inbetween plane  BPQ  and plane CPQ is PQ

Step-by-step explanation:


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Select the correct answer.
Effectus [21]

Answer:c

Step-by-step explanation:

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3 years ago
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Which is better buy? 5 lb of flour for $0.90 or<br> 8 lb for $1.25
Ludmilka [50]
Well let’s see if there’s a least common multiple of 5 and 8. Since 40 is the least common mult. We will multiply 40 x .90 and 40 x 1.25 . 40x.90 is 36 while 40x1.25 is 50. It’s better to buy eight pounds for 1.25!
4 0
2 years ago
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Find the distance between (5, -4) and (-1, -2)
Arisa [49]

Answer: The distance is sqrt(40).

Step-by-step explanation:

Let's use the Pythagorean Theorem (a^2 + b^2 = c^2)

(Look at the image I attached)

Let's set a = 2 and b = 6. The mystery side is c, which is opposite to the right angle that is formed when you draw perpendicular lines from each of the points.

(2)^2 + (6)^2 = c^2 <--- First, we need to simplify

4 + 36 = c^2

40 = c^2 <--- Now, we need to take the square root of both sides.

c = sqrt(40)

So, the distance between (5, -4) and (-1, -2) is sqrt(40). I recommend looking at some videos on Khan Academy if you need more help! Let me know if you want me to attach a link that you can visit.

5 0
3 years ago
On payday you received a check for $320 and took it to the bank to cash it. You received 25 bills made up of $5's and $20's. How
Sunny_sXe [5.5K]
The answer will be 11 dollar bills
8 0
3 years ago
Factorise (2t-7)²-(5t-4)² <br>with working pls​
sertanlavr [38]

Answer:

33+12t−21t^2

Step-by-step explanation:

(2t-7)²-(5t-4)²

Use binomial theorem (a−b)^2 = a^2−2ab+b^2 to expand (2t-7)².

4t^2−28t+49−(5t-4)²

Use binomial theorem (a−b)^2 = a^2−2ab+b^2 to expand (5t-4)².

4t^2−28t+49−(25t^2−40t+16)

To find the opposite of 25t^2

−40t+16, find the opposite of each term.

4t^2−28t+49−25t^2−40t+16

Combine 4t^2  and −25t^2  to get −21t^2.

−21t^2−28t+49+40t−16

Combine −28t and 40t to get 12t.

−21t^2+12t+49−16

Subtract 16 from 49 to get 33.

−21t^2+12t+33

Swap terms to the left side.

33+12t−21t^2

I hope this helped!

5 0
3 years ago
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