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a_sh-v [17]
3 years ago
15

Q#1: Suppose that you have two different algorithms for solving a problem. To solve a problem of size n, the first algorithm use

s exactly n*exp1-[n+2n+3n+4n]/nlne(10) operations and the second algorithm uses exactly n! operations. As n grows, which algorithm uses fewer operations?
Mathematics
1 answer:
svetlana [45]3 years ago
7 0

Answer:

The one of -[n+2n+3n+4n]/nlne(10) has fewer operations because the value of n is <u>static</u><u>.</u>

The one of n! ( factorial ) is factorised up to n∞ hence has infinity operations.

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3 years ago
Find all polar coordinates of point P where P = ordered pair 3 comma negative pi divided by 3 .
jek_recluse [69]

Answer:

The all polar coordinates of P are:

(3 , -π/3) , (3 , 5π/3) , (-3 , 2π/3) , (-3 , -4π/3)

Step-by-step explanation:

* Lets study the polar coordinates of a point

- In polar coordinates there is an infinite number of coordinates

 for a given point.

- The polar coordinates of a point (x , y) is (r , θ), where

  r = √ ( x2 + y2 )

  θ = tan-1 ( y / x )

# Ex: the following four points are all coordinates for the same point.

* (5 , π/3) = (5 , −5π/3) = (−5 , 4π/3) =(−5 , −2π/3)

- These four points only represent the coordinates of the point without  

  rotating more than once

- So the point (r,θ) can be represented by any of the following

  coordinate pairs  (r , θ + 2π n) and (−r , θ + (2n + 1) π), where n is

  any integer.

* Now lets solve the problem

∵ P = (3 , -π/3)

∵ (r , θ + 2πn)

∴ r = 3 an d Ф = -π/3

- let n = 1

∴ P = (3 , -π/3 + 2π)

∴ P = (3 , 5π/3)

∵ P =(3 , -π/3)

∵ P = (-r , θ + (2n + 1) π)

Let n = 0

∴ P = (-3 , -π/3 + (2×0 + 1) π)

∴ P = (-3 , -π/3 + (0 + 1) π)

∴ P = (-3 , -π/3 + π)

∴ P = (-3 , 2π/3)

∵ P =(3 , -π/3)

∵ P = (-r , θ + (2n + 1) π)

Let n = -1

∴ P = (-3 , -π/3 + (2(-1) + 1) π)

∴ P = (-3 , -π/3 + (-2 + 1) π)

∴ P = (-3 , -π/3 + -π) = (-3 , -4π/3)

∴ P = (-3 , -4π/3)

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3 years ago
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Which of the choices below is not a possible correlation coefficient?
fiasKO [112]

Answer:

The condition for r is the following:

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And for this case if we analyze the options the only impossible value is given by:

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Step-by-step explanation:

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And for this case if we analyze the options the only impossible value is given by:

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