Answer:
f(x) = 4.35 +3.95·sin(πx/12)
Step-by-step explanation:
For problems of this sort, a sine function is used that is of the form ...
f(x) = A + Bsin(2πx/P)
where A is the average or middle value of the oscillation, B is the one-sided amplitude, P is the period in the same units as x.
It is rare that a tide function has a period (P) of 24 hours, but we'll use that value since the problem statement requires it. The value of A is the middle value of the oscillation, 4.35 ft in this problem. The value of B is the amplitude, given as 8.3 ft -4.35 ft = 3.95 ft. Putting these values into the form gives ...
f(x) = 4.35 + 3.95·sin(2πx/24)
The argument of the sine function can be simplified to πx/12, as in the Answer, above.
B. Warm air rises,and cool air sinks.
Number 15 is 80 i dont know about the others...sorry
The month of January has 31 days, so from January 1st to February 14th, there are 31 + 14 or 45 days, namely x = 45.
y = 3.06 * sin[ 0.017(45) - 1.40 ] + 12.23.
make sure your calculator is in Degree mode.
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