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Black_prince [1.1K]
3 years ago
15

A trader bought x mangoes at the rate of 4 mangoes for 10 naira, five of the mangoes were bad so he sold the remaining at the ra

te of 5 mangoes for 20 naira and he made a gain of 10 naira how many mangoes did he buy?
Mathematics
1 answer:
Artemon [7]3 years ago
8 0

Answer:

  20

Step-by-step explanation:

The cost of the x mangoes was ...

  c = 10(x/4)

The revenue from the sale of mangoes was ...

  r = 20(x-5)/5

The profit is the difference between revenue and cost:

  10 = r - c = 20(x -5)/5 -10(x/4) = 1.5x -20 . . . . substitute and simplify

  30 = 1.5x . . . . . add 20

  20 = x . . . . . . . .divide by 1.5

The trader bought 20 mangoes.

_____

<em>Check</em>

He paid 20(10/4) = 50 naira. He sold the 15 good mangoes for 20/5(15) = 60 naira, so made a 10 naira profit.

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enyata [817]

Answer:

40x - 300,000

7,500

Step-by-step explanation:

profit  = revenue - cost

p(x) = 75x - (35x + 300,000)

p(x) = 40x - 300,000

Break even is when profit is zero

40x - 300,000 = 0

40x = 300,000

x = 7,500

4 0
2 years ago
First you to find the worksheet and download it<br> plase I need help
Goshia [24]

Answer:

a) The horizontal asymptote is y = 0

The y-intercept is (0, 9)

b) The horizontal asymptote is y = 0

The y-intercept is (0, 5)

c) The horizontal asymptote is y = 3

The y-intercept is (0, 4)

d) The horizontal asymptote is y = 3

The y-intercept is (0, 4)

e) The horizontal asymptote is y = -1

The y-intercept is (0, 7)

The x-intercept is (-3, 0)

f) The asymptote is y = 2

The y-intercept is (0, 6)

Step-by-step explanation:

a) f(x) = 3^{x + 2}

The asymptote is given as x → -∞, f(x) = 3^{x + 2} → 0

∴ The horizontal asymptote is f(x) = y = 0

The y-intercept is given when x = 0, we get;

f(x) = 3^{0 + 2} = 9

The y-intercept is f(x) = (0, 9)

b) f(x) = 5^{1  - x}

The asymptote is fx) = 0 as x → ∞

The asymptote is y = 0

Similar to question (1) above, the y-intercept is f(x) = 5^{1  - 0} = 5

The y-intercept is (0, 5)

c) f(x) = 3ˣ + 3

The asymptote is 3ˣ → 0 and f(x) → 3 as x → ∞

The asymptote is y = 3

The y-intercept is f(x) = 3⁰ + 3= 4

The y-intercept is (0, 4)

d) f(x) = 6⁻ˣ + 3

The asymptote is 6⁻ˣ → 0 and f(x) → 3 as x → ∞

The horizontal asymptote is y = 3

The y-intercept is f(x) = 6⁻⁰ + 3 = 4

The y-intercept is (0, 4)

e) f(x) = 2^{x + 3} - 1

The asymptote is 2^{x + 3}  → 0 and f(x) → -1 as x → -∞

The horizontal asymptote is y = -1

The y-intercept is f(x) =  2^{0 + 3} - 1 = 7

The y-intercept is (0, 7)

When f(x) = 0, 2^{x + 3} - 1 = 0

2^{x + 3} = 1

x + 3 = 0, x = -3

The x-intercept is (-3, 0)

f) f(x) = \left (\dfrac{1}{2} \right)^{x - 2} + 2

The asymptote is \left (\dfrac{1}{2} \right)^{x - 2} → 0 and f(x) → 2 as x → ∞

The asymptote is y = 2

The y-intercept is f(x) = f(0) = \left (\dfrac{1}{2} \right)^{0 - 2} + 2 = 6

The y-intercept is (0, 6)

7 0
2 years ago
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givi [52]

Answer:

x = 11

Step-by-step explanation:

Given

Parallel lines A and B

Required

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This means that

5x + 9 = 6x - 2

Collect like terms

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-x = -11

Multiply both sides by -1

-1 * -x = -11 * -1

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3 years ago
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Answer:

FOIL:  9x^2 +30xy + 25y^2

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3 years ago
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2 years ago
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