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A researcher wished to compare the effect of two stepping heights (low and high) on heart rate in a step-aerobics workout. A col

Alinara [238K]

Answer:

The answer is "between 0.10 and 0.05".

Step-by-step explanation:

For sample 1:

$n_1 = 25\\\\\bar{x_1} = 90.00\\\\ s_1 = 9\\\\$

For sample 2:

$n_2 = 25\\\\ \bar{x_2} = 95.08\\\\ S_2 = 12\\\\$

Calculating the null and alternative hypotheses:

$H_O : \mu_1 = \mu_2 \\\\ H_Q : \mu_1$

Calculating the test statistic:

$Z= \frac{90-95.08}{ \sqrt{\frac{9^2}{25}+\frac{12^2}{25}}} \\\\ =\frac{-5.08}{ \sqrt{\frac{81}{25}+\frac{144}{25}}}\\\\=\frac{-5.08}{ \sqrt{\frac{81+144}{25}}}\\\\=\frac{-5.08}{ \sqrt{\frac{225}{25}}}\\\\=\frac{-5.08}{ \frac{15}{5}}\\\\=\frac{-5.08}{3}\\\\= -1.693$

Calculating the conservative degrees of freedom:

$DF = min (n_1 -1, n_2 - 1) = min(25-1, 25-1) = 24$

by using Excel the p-value for left tailed test and for test statistic will be $-1.693$ with $DF = 24$ .

$\to p-value = TDIST(1.693, 24, 1) = 0.0517\ \ \ \ i.e, \bold{0.05 < p-value < 0.10}$

5 0

3 years ago

You get a summer job and make a total of $5,500 throughout the summer months. The government takes out taxes from that money at

bonufazy [111]

Answer:

$1650 is the answer hope it helps

8 0

2 years ago

Find the measure of each angel if m angle 8 = 115º

zalisa [80]

Lines p and q are parallel.
Corresponding angles are congruent.
Each two adjacent angles are supplementary.
Vertical angles are congruent.

Angles 7 and 8 are adjacent, supplementary angles.
m<7 + m<8 = 180
m<7 + 115 = 180
m<7 = 65

Angles 6 and 8 are corresponding angles and congruent.
m<6 = m<8
m<6 = 115

Angles 1 and 6 are vertical angles and congruent.
m<1 = m<6
m<1 = 115

7 0

3 years ago

Find a cubic polynomial that goes through points (4, – 22) and (3, - 26) and has tangents with slopes

Salsk061 [2.6K]

Let f(x) = ax ³ + bx ² + cx + d.

The graph of f(x) passes through (4, -22) and (3, -26), which means f (4) = -22 and f (3) = -26, so that

64a + 16b + 4c + d = -22

27a + 9b + 3c + d = -26

When the question says it has tangents at some point, I take that to mean the slope of the tangent line at that point is the given number. So f ' (4) = 11 and f ' (3) = -2. We have

f '(x) = 3ax ²+ 2bx + c

so that

48a + 8b + c = 11

27a + 6b + c = -2

Solve the system:

• Eliminate d :

(64a + 16b + 4c + d) - (27a + 9b + 3c + d) = -22 - (-26)

→ 37a + 7b + c = 4

• Eliminate c :

(48a + 8b + c) - (27a + 6b + c) = 11 - (-2)

→ 21a + 2b = 13

(48a + 8b + c) - (37a + 7b + c) = 11 - 4

→ 11a + b = 7

• Eliminate b, then solve for a and the other variables:

(21a + 2b) - 2 (11a + b) = 13 - 2 (7)

-a = -1

a = 1 → b = -4 → c = -5 → d = -2

Then

f(x) = x ³ - 4x ² - 5x - 2

7 0

4 years ago

3: A car travels 120 miles in 3 hours at a steady speed.

maks197457 [2]

Answer:

40 in 1 hour

320 in 8 hours

Step-by-step explanation:

3 0

3 years ago