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Ilia_Sergeevich [38]
3 years ago
11

A pet store worker weighs each kitten to the

Mathematics
1 answer:
erik [133]3 years ago
6 0
I think The answer is B
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Suppose that 20% of the employees of a given corporation engage in physical exercise activities during the lunch hour. Moreover,
Harlamova29_29 [7]

Answer:

a) 0.152 = 15.2% probability that this person is a female who engages in physical exercise activities during the lunch hour.

b) 0.248 = 24.8% probability that this person is a female who does not engage in physical exercise activities during the lunch hour.

Step-by-step explanation:

Question a:

20% of employees engage in physical exercise.

This 20% is composed by:

8% of 60%(males)

x% of 100 - 60 = 40%(females).

Then, x is given by:

0.08*0.6 + 0.4x = 0.2

0.4x = 0.2 - 0.08*0.6

x = \frac{0.2 - 0.08*0.6}{0.4}

x = 0.38

0.38 = 38%

Probability of being a female who engages in exercise:

40% are female, 38% of 40% engage in exercise. So

0.38*0.4 = 0.152

0.152 = 15.2% probability that this person is a female who engages in physical exercise activities during the lunch hour.

B. If we choose an employee at random from this corporation,what is the probability that this person is a female who does not engage in physical exercise activities during the lunch hour?

40% are female, 100% - 38% = 62% of 40% do not engage in exercise. So

0.62*0.4 = 0.248

0.248 = 24.8% probability that this person is a female who does not engage in physical exercise activities during the lunch hour.

3 0
3 years ago
Im answering questions on here instead of doing my own school work lol
zhenek [66]

Answer:

omg sameeee

Step-by-step explanation:

lol

3 0
3 years ago
Which answer shows a reflection across the y-axis?
prohojiy [21]
The answer would be D.
4 0
3 years ago
Read 2 more answers
Sin Z = <br><br> Cos Z = <br><br> Tan Z =
Daniel [21]

sin z= z/y

cos z= x/y

tan z= z/x

4 0
3 years ago
In a recent study of 42 eighth graders, the mean number of hours per week that they watched television was 19.6. Assume the popu
olya-2409 [2.1K]

Answer:

19.6-2.42\frac{5.8}{\sqrt{42}}=17.43    

19.6+2.42\frac{5.8}{\sqrt{42}}=21.77    

And the best option for this case would be:

a. (17.5, 21.7)

Step-by-step explanation:

Information given

\bar X= 19.6 represent the sample mean

\mu population mean

\sigma= 5.8 represent the population deviation

n=42 represent the sample size  

Confidence interval

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

The degrees of freedom, given by:

df=n-1=42-1=41

Since the Confidence is 0.98 or 98%, the significance would be \alpha=0.02 and \alpha/2 =0.1, and the critical value would be t_{\alpha/2}=2.42

Replacing we got:

19.6-2.42\frac{5.8}{\sqrt{42}}=17.43    

19.6+2.42\frac{5.8}{\sqrt{42}}=21.77    

And the best option for this case would be:

a. (17.5, 21.7)

8 0
3 years ago
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