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2 years ago

Please help me on this one. I don't know the equation to solve it. I really need help!!

Mathematics

1 answer:

BigorU [14]2 years ago

4 0

I can't see the question it's blurry

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if You flip an coin 200 times about how many times would you expect the coin to labd on tails what is the probality

inysia [295]

Answer:

100;200

There are 200 total flips and to find probability we would have to divide it by two. Doing so, should give you something like this 100;200.

4 0

2 years ago

A piece of wire 23 m long is cut into two pieces. One piece is bent into a square and the other is bent into an equilateral tria

AURORKA [14]

Answer:

For maximum area, all of the wire should be used to construct the square.

The minimum total area is obtained when length of the wire is 10m

Step-by-step explanation:

For maximum, we use the whole length

For minimum,

supposed the x length was used for the square,

the length of the side of the square = x/4m

Area = $\frac{x^{2} }{16}$

For the equilateral triangle, the length of the side = $\frac{23 - x}{3}$

Area = $\frac{\sqrt{3} }{4} a^{2} = \frac{\sqrt{3} }{4} (\frac{23 - x}{3} )^{2}$

Total Area = $\frac{x^{2} }{16}$ + $\frac{\sqrt{3} }{36} (23-x)^{2}$

$\frac{dA}{dx} = \frac{x}{8} - \frac{\sqrt{3} }{18} (23 - x)\\$

$\frac{d^{2}A }{dx^{2} } = \frac{1}{8} + \frac{\sqrt{3} }{18} > 0$ , therefore it is minimum

$\frac{dA}{dx} = 0 \\\\$

$\frac{x}{8} - \frac{\sqrt{3} }{18} (23 - x) = 0\\$

x = 10.00m

3 0

2 years ago

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Help with math:) 6th grade!!!

kvv77 [185]

Answer:

yeah, its 64

Step-by-step explanation:

4 0

2 years ago

Gravity pulls the metal down at 10 N, but the metal pieces RISES! At least how much force is needed to make it move upward?

prisoha [69]

Answer: Greater than 10 N

Step-by-step explanation:

Given

Gravity force on metal is 10 N

But the metal piece is rising i.e. there must be an upward force greater than 10 N

Suppose the force is F

So, we can write

$\Rightarrow F>10\ N$

Any force greater than 10 N is sufficient for the metal to move upwards

The greater the amount of force faster will be the movement

3 0

2 years ago

The point (0,-4) is located [ANSWER]

natka813 [3]

Answer:

on the x-axis

Step-by-step explanation:

it is located on the x axis because it is not technically in any quandrant. it is however, on an axis.

3 0

2 years ago

Read 2 more answers