Find the zeros<span> of Function (</span>x)= (x+3)^2(x-5)^6 and state the multiplicity. ... (x--5)^6<span> = 0=> </span>x--5<span>= 0 => </span>x<span> = </span>5<span>. Therefore real </span>zero's of the function<span> are --</span>3<span>,5.</span><span />
<span>well one fraction that would be equal to 0.4 would be two fifths another would be four tenths and the last one would be six fifteenths.</span>
She has 8 dimes, 11 quarters, and 22 nickels
43.586- anything 5 and more rounds up, so the 6 rounds the 8 up to 9, the 9 rounds the 5 up to a 6, so your answer wound be 43.6 because 43.5(tenths)8(hundredths)6(thousandths), i hope this helps
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12 + 0.15m = 10 + 0.25m
0.15m - 0.25m = 10 - 12
- 0.10m = -2
m = -2/-0.10
m = 20
At 20 miles, the cost of the two taxi services will be the same.
