In order to compute the mass of each solute in the sample, we simply multiply the percentage mass of each solute with the total mass of the solution. This is ad such:
Mass (NaCl) = 0.0486 x 294
Mass (NaCl) = 14.29 grams
Mass(Na₂CO₃) = 0.0754 x 294
Mass(Na₂CO₃) = 22.17 grams
Answer: 3.5 moles V2O5
Explanation: First balance the chemical equation to find the stoichiometric factor between VOCl3 and V2O5
2 V2O5 + 6 Cl2 => 4 VOCl3 + 7 O2
So the mole to mole ratio is 2 moles V2O5 to 4 moles of VOCl3
Solution
7 moles VOCl3 x 2 moles V2O5 / 4 moles VOCl3 = 3.5 moles V2O5
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