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Artemon [7]
3 years ago
8

AP CHEMISTRY -If any of these questions in the image (NET IONIC BALANCED EQUATIONS w/ states of matter) can be answered, especia

lly with how, would be amazing.

Chemistry
1 answer:
OLga [1]3 years ago
5 0

3) CH₃-COOH + NH₃ → CH₃-COO⁻NH₄⁺

4) 2 FeCl₃ + 3 Ag₂SO₃ → Fe₂(SO₃)₃ + 6 AgCl

5) 2 Al + 3 NiCl₂ → 2 AlCl₃ + 3 Ni

6) 4 LiCl + Pb(NO₂)₄ → 4 LiNO₂ + PbCl₄

7) 3 H₂SO₄ + 2 Al(OH)₃ → Al₂(SO₄)₃ + 6 H₂O

8) Cd(NO₃)₂ + Na₂S → CdS + 2 NaNO₃

9) Cr₂(SO₄)₃ + 3 (NH₄)₂CO₃ → Cr₂(CO₃)₃ + 3 (NH₄)₂SO₄

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What is the greatest source of radiation most humans are exposed to
Scilla [17]
The greatest source of radiation is radon gas
8 0
2 years ago
The mass of an atom of element x is equivalent to the total mass of 7 hydrogen atoms
Sergeu [11.5K]
Hydrogen mass is 1, the atom with mass number 7 is Lithium
4 0
2 years ago
Consider the following balanced equation:
algol [13]

Moles of PF₃ : 4

<h3>Further explanation</h3>

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.

Reaction

\tt P_4(s)+6F_2(g)\rightarrow 4PF_3(g)

1.25 moles of P₄(s) is reacted with 6 moles of F₂(g)

Limiting reactant : the smallest ratio (mol divide by coefficient)

P₄ : F₂ =

\tt \dfrac{1.25}{1}\div \dfrac{6}{6}=1.25\div 1\rightarrow F_2~limiting~reactant(smallest~ratio)

mol PF₃ based on mol of limiting reactant(F₂), so mol PF₃ :

\tt \dfrac{4}{6}\times 6~moles=4~moles

8 0
3 years ago
What 2 pieces of equipment will you use to separate the salt from the water?
uysha [10]

Separate Salt and Water Using Distillation

If you want to collect the water, you can use distillation. This works because salt has a much higher boiling point than water. One way to separate salt and water at home is to boil the salt water in a pot with a lid.

hope this helps!!

8 0
2 years ago
NH3 is a weak base (Kb = 1.8 × 10–5) and so the salt NH4Cl acts as a weak acid. What is the pH of a solution that is 0.084 M in
kolbaska11 [484]
Answer is: pH of solution is 5,17.
Kb(NH₃) = 1,8·10⁻⁵.
c(NH₄Cl) = 0,084 M = 0,084 mol/L.
Chemical reaction: NH₄⁺ + H₂O → NH₃ + H₃O⁺.
Ka · Kb = 10⁻¹⁴.
Ka(NH₄⁺) = 10⁻¹⁴ ÷ 1,8·10⁻⁵.
Ka(NH₄⁺) = 5,55·10⁻¹⁰.
[H₃O⁺] = [NH₃]  = x.
Ka(NH₄⁺) = [H₃O⁺] · [NH₃] ÷ [NH₄⁺].
5,55·10⁻¹⁰ = x² ÷ (0,084 M - x).
Solve quadratic equation: x = [H₃O⁺] = 6,8·10⁻⁶ M.
pH = -log[H₃O⁺].
pH = -log(6,8·10⁻⁶ M) = 5,17.
7 0
3 years ago
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