The atomic number of Fluorine is 9
Valence (outer) electron configuration is : 2s²2p⁵
Therefore, it requires 1 electron in the p-orbital to complete its octet of 8 electrons.
Thus, the atom Fluorine generally will become <u>more </u>stable through the formation of an ionic chemical compound by accepting <u>1 </u> electron from another atom. This process will fill its outer energy level.
Ans: A) more, 1
Answer:
False
Explanation:
Every chemical element undergoes a reaction in order to fulfill the completion of their outermost shell. This is the case of nitrogen (symbol "N"), which is an element found in group 5 of the periodic table with atomic number 7 (i.e. 1s2 2s2 2p3). It possesses three valence electrons in it's outermost shell.
Looking at the configuration of the Nitrogen atom, it requires three electrons to complete its electron shell. Hence, nitrogen will enter a reaction in order to have its need for THREE ELECTRONS met in order to have its electron shell full.
Note that, nitrogen enters a chemical reaction to look for three electrons not three neutrons.
Pressure decreases when you open the top. Pressure decreases, which favors the formation of H2CO3.
I better get your number.
Answer:
Explanation:
Firstly of all we have to construct the min-heap of the k-sub list and each sub list which is a node in the constructed min-heap.
We have several steps to follows:
Step-1. When we compare the two sub lists, at the starting we can compare their first elements which is actually their minimum elements.
Step-2. The min-heap formation will cost be O(k) time.
Step-3. After the step 1 & step 2 we can run the minimum algorithm which can be extracted from the minimum element in the root list.
Step-4. Then Update the root list in the heap and after that simplify the min-heap as maintained by the new minimum element in the root list.
Step-5. If any root sub-list becomes empty in the step 4 then we can take any leaf sub-list from the root and simplify it.
Step-6. At every Extraction of the element it can take up to O(log k) time.
Hence, We can say that the extract of n element in the total whose
Running time will be O(n log k + k) which can be equal to the O(n log k+ k) (since k < n).
Answer:
Group B is the control group
Explanation:
In an experiment, a control group is the standard to which comparisons are made in an experiment.
