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den301095 [7]
4 years ago
15

How do you know that a =6 is a solution to a+5=11?

Mathematics
2 answers:
Mkey [24]4 years ago
8 0

We are given this equation a+5=11

here 5 is in addition on the left side

so in order to eliminate it , we perform opposite operation of addition on the right side.

opposite operation of addition is subtraction.

so subtracting 5 on the right side , we get

a=11-5

a=6

so this is how a=6 is the answer

NNADVOKAT [17]4 years ago
7 0

a + 5 = 11

You need to isolate the variable by subtracting from both sides

a + 5 - 5 = 11 - 5a = 6

The Addition/Subtraction Property of Equality states that if you add or subtract the same number to both sides of an equation the two sides still remain equal.

:))

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Find the slope of the line passing through the points (-6, 6) and (4. – 7).
postnew [5]

Answer:

\displaystyle -\frac{13}{10}

Step-by-step explanation:

To solve this problem, first you have to use the slope formula of \displaystyle \frac{y_2-y_1}{x_2-x_1}.

y2= (-7)

y1=6

x2=4

x1(-6)

Solve.

\displaystyle \frac{(-7)-6}{4-(-6)}=\frac{-13}{10}=\boxed{-\frac{13}{10}}

Therefore, the correct answer is -13/10.

6 0
4 years ago
Read 2 more answers
How many trucks carried only late variety?
murzikaleks [220]

9514 1404 393

Answer:

  • late only: 15
  • extra-late only: 24
  • one type: 43
  • total trucks: 105

Step-by-step explanation:

It works well when making a Venn diagram to start in the middle (6 carried all three), then work out.

For example, if 10 carried early and extra-late, then only 10-6 = 4 of those trucks carried just early and extra-late.

Similarly, if 30 carried early and late, and 4 more carried only early and extra-late, then 38-30-4 = 4 carried only early. In the attached, the "only" numbers for a single type are circled, to differentiate them from the "total" numbers for that type.

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a) 15 trucks carried only late

b) 24 trucks carried only extra late

c) 4+15+24 = 43 trucks carried only one type

d) 38+67+56 -30-28-10 +6 +6 = 105 trucks in all went out

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3 years ago
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6 0
3 years ago
Complete the equation of the line through (3,-8)(3,−8)left parenthesis, 3, comma, minus, 8, right parenthesis and (6,-4)(6,−4
miv72 [106K]
y=mx+b
(3;-8)\rightarrow x=3;\ y=-8;\ (6;-4)\rightarrow x=6;\ y=-4

substitute:\\\\  \left\{\begin{array}{ccc}-8=3m+b\\-4=6m+b&|\cdot(-1)\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}-8=3m+b\\4=-6m-b\end{array}\right}\ \ \ |add\ both\ sides\\.\ \ \ \ -4=-3m\ \ \ |:(-3)\\.\ \ \ \ m=\dfrac{4}{3}\\\\substitute\ the\ value\ of\ m\ to\ first\ equation:\\\\3\cdot\dfrac{4}{3}+b=-8\\\\4+b=-8\ \ \ |-4\\b=-12\\\\Answer:\boxed{y=\dfrac{4}{3}x-12}
4 0
3 years ago
5=|y+3| what is the answer
Alexeev081 [22]
2 = y because 2+3= 5
5 0
3 years ago
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